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Ghella [55]
3 years ago
5

Use the graph of f to estimate the local maximum and local minimum. Local maximum: (0,1); local minimum: three pi over two, nega

tive 1 and negative pi, negative 1 Local maximum: (0,0) and approx (0,1); local minimum: negative three pi over two, negative 1 Local maximum: (0,0); local minimum: three pi over two, negative 1 Local maximum: (0,1); local minimum: approx. (0,0) and three pi over two, negative 1

Mathematics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

The answer is A.

Step-by-step explanation:

Local maximums are whenever the graph reaches it's highest <em>y</em> value.

Local minimums are whenever the graph reaches it's lowest <em>y</em> value.

From the graph, we can see that the maximum y-value the graph reaches is y=1. And this happens when x=0.

This only happens once (from the graph shown). Thus, the local maximum would be:

(0,1)

The minimum values we can see from the graph is at y=-1. This happens twice from the graph, once at -π and again at 3π/2.

Thus, the local minimums are:

(-\pi,-1), (3\pi/2,-1)

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Solve this question now ​
sattari [20]

Answer:

Center is (1,5) ;Radius is the square root of 13

3 0
3 years ago
0/3 x 11 &gt; 11 , whats the empty 0?
Cloud [144]

Answer:

This inequalitie is wrong because 0 is not more than 11

Step-by-step explanation:

8 0
3 years ago
Convert the polar equation r = 2 secØ to a Cartesian equation.y = 2x = 2x^2 = 2
ss7ja [257]
Polar and cartesian equation<h2>Initial explanation</h2>

Let's analyze the relation between r and x and y:

We have that between the indicated value of r (of the polar coordinates) and x and y (of the cartesian coordinates) there is a relation because they form a triangle. If r changes, then the value of x and y will change.

<h2>STEP 1: given equation</h2>

Using the given equation

r = 2 secØ

we have that

\begin{gathered} r=2secØ \\ \downarrow \\ \frac{r}{2}=secØ \end{gathered}<h2>STEP 2: secØ equation</h2>

Observing the image of the initial explanation we have a right triangle, we know that the equation of

secØ for any right triangle is given by:

\sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}

In this case,

hypotenuse = r

adjacent side = x

then,

\begin{gathered} \sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}=\frac{r}{x} \\ \sec Ø=\frac{r}{x} \end{gathered}<h2>STEP 3: comparison between given equation and secØ equation</h2>

Then, we have that:

\begin{gathered} \sec Ø=\frac{r}{x} \\ \sec Ø=\frac{r}{2} \end{gathered}

This means that:

\begin{gathered} \frac{r}{x}=\sec Ø=\frac{r}{2} \\ \downarrow \\ \frac{r}{x}=\frac{r}{2} \end{gathered}

Then,

x = 2

The equation in cartesian coordinates is x=2.

Answer: x=2

6 0
1 year ago
Leland was able to build 1/4 of a shelf in 2/3 of an hour. How many shelves can he build per hour?​
Gre4nikov [31]

Answer:

7/20 of one shelf in an hour

Step-by-step explanation:

if you think about the problem in numbers out of 100, we know that

- 2/3 of an hour is 40 minutes per hour because 60/3 = 20

- 1/4 of a shelf is 25% of the shelf

In an hour Leland can build 35% of a shelf in an hour or 7/20 of a shelf

7 0
3 years ago
Does anyone know what this is ?
Natasha_Volkova [10]

9514 1404 393

Answer:

  x = 2

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relations between trig functions and angle.

  Tan = Opposite/Adjacent

  tan(θ) = y/x

  Sin = Opposite/Hypotenuse

  sin(θ) = y/4

The given relation is ...

  tan(θ) = 2·sin(θ)

  y/x = 2(y/4)

  2 = x . . . . . . . multiply by (2x/y)

_____

<em>Additional comment</em>

Then the angle can be found from the relation ...

  Cos = Adjacent/Hypotenuse

  cos(θ) = x/4 = 2/4 = 1/2

  θ = arccos(1/2) = 60°

and the value of y is ...

  y = 4·sin(60°) = 2√3

3 0
3 years ago
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