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trasher [3.6K]
3 years ago
14

Given: Circumscribed polygon ABCD AB=21, BC=24, CD=30 Find: AD AD = ____ units

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer:

AD = 27 units

Step-by-step explanation:

In the above question, we have a circumscribed Polygon, were circle XYZ is inside the polygon ABCD

We were given the following side

AB=21 units

BC=24 units

CD=30 units

Side AB = AW + BW

21 units = x + 21 - x

Side BC = BX + CX

BX = BW , hence BX = 21 - x

Side BC = 21 units

24 = 21 - x + CX

CX = 24 - (21 - x)

CX = 24 - 21 + x

CX = 3 + x

Side CD = CY + DY

Note that: CY = CX, hence, CY = 3 + x

Side CD = 30 units

30 = 3 + x + DY

DY = 30 - (3 + x)

DY = 30 - 3 - x

DY = 27 - x

Side AD = AZ + DZ

Note also that:

AZ = AW , hence AZ = x

DY = DZ , hence DZ = 27 - x

Side AD = x + 27 - x

Side AD = 27 units

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Step-by-step explanation:

Notice that when x = - 1. then dy/dx becomes:

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therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:

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3 years ago
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answers please asap for this question please i have been waiting for ever and its due tomorrow the 10th
ololo11 [35]
Hi there!

First, let's create an equation for the table: m = 2n + 40. Using this equation, we can find the values of x, y, and z.

WORK:
x = 2(4) + 40
x = 8 + 40
x = 48
y = 2(5) + 40
y = 10 + 40
y = 50
z = 2(6) + 40
z = 12 + 40
z = 52

Next, using the equation, we know that the initial investment would be 40, since that is the y-intercept of the equation. To express M in terms of N, that would be our equation m = 2n + 40. To find 10 years, we'll plug in 10 for n.

WORK:
m = 2(10) + 40
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m = 60 after 10 years

To figure out when his investment would double, we'll need to use 80 (double his initial investment of 40) in place of m.

WORK:
80 = 2n + 40
40 = 2n
n = 20 years


Hope this helps!! :)
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