Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
y = 2x - 19
Step-by-step explanation:
Graph the points on the table and you'll be able to see the answer. That's how I went about it.
or use m = y^2 - y^1 divided by x^2 - x^1 to find the slope, then solve for the initial value from there
There must be something missing there is no possible way to answer the question without a variable.
Answer:
Thats and area of a circular cylinder
Step-by-step explanation:
yeah thats all
Answer:
Noooooooooooooooooooooooooooo