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lesya692 [45]
2 years ago
9

What does it mean to be a Rigid Motion? Name 3 Rigid Motions that we discussed in Semester A:​

Mathematics
1 answer:
never [62]2 years ago
8 0

Answer:

A Rigid Motion is a transformation that preserves length (distance preserving) and angle measure (angle preserving). Another name for a rigid motion is an isometry. A direct isometry preserves distance and orientation. Translations and Rotations are direct isometries.

Step-by-step explanation:

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Solve the proportion:<br> -9/6 = 3/x
hichkok12 [17]

Answer:

-2

Step-by-step explanation:

6 0
3 years ago
There are 20 squid and 36 eels in a fish tank. What is the ratio of squids to eels? What is the rate of squids to eels? What abo
Ira Lisetskai [31]

Answer:

Ratio: 20:36

Rate: 20 squids per 36 eels

Simplified ratio:

=  \frac{20}{36 }  = \frac{10}{18}  =  \frac{5}{9}

Unit ratio:

20/36 squids per eel (dividing by 36)

Please mark Brainliest if this helps!

7 0
3 years ago
Read 2 more answers
Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the
tangare [24]

Answer:

Option D) h(x), f(x), g(x)

Step-by-step explanation:

we know that

The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex of the parabola

Part 1) we have

f(x)=4x^{2} -1

This is a vertical parabola open upward

The vertex is a minimum The vertex is the point (0,-1)

The x-coordinate of the vertex is 0

so

The axis of symmetry is x=0

Part 2) we have

g(x)=x^{2}-8x+5

This is a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

g(x)-5=x^{2}-8x

g(x)-5+16=x^{2}-8x+16

g(x)+11=x^{2}-8x+16

g(x)+11=(x-4)^{2}

g(x)=(x-4)^{2}-11

The vertex is the point (4,-11)

The x-coordinate of the vertex is 4

so

The axis of symmetry is x=4

Part 3) we have

h(x)=-3x^{2}-12x+1

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

h(x)-1=-3x^{2}-12x

h(x)-1=-3(x^{2}+4x)

h(x)-1-12=-3(x^{2}+4x+4)

h(x)-13=-3(x+2)^{2}

h(x)=-3(x+2)^{2}+13

The vertex is the point (-2,13)

The x-coordinate of the vertex is -2

so

The axis of symmetry is x=-2

Part 4) Rank their axis of symmetry from least to greatest

1) h(x) -----> axis of symmetry -2

2) f(x) -----> axis of symmetry 0

3) g(x) -----> axis of symmetry 4

so

h(x),f(x),g(x)

7 0
3 years ago
Solve the inequality |4x +4| &lt; 12
mel-nik [20]

Start by dividing all terms by 4, to reduce this expression: |x+1| < 3.

Case 1: x+1 is already positive. The abs. val. operator does not change

anything. Then x+1<3, or x<2.

Case 2: (x+1) is negative. The abs. val. operator, in effect, puts a - sign in

front of (x+1): -(x+1)<3. Distributing the - sign: -x - 1 < 3. Adding 1 to both sides: -x < 4. We want to solve for positive x, so we mult. both sides of

-x<4 by -1 AND change the direction of the inequality symbol:

x > -4

Thus, the solution set is (-4,2): All real numbers between -4 and 2.


5 0
3 years ago
Read 2 more answers
Given a point A(-3,-1), it is dilated by some scale
Sidana [21]

Answer:

B' = (-3, -15)

Step-by-step explanation:

Given

A = (-3,-1)

A' = (-9,-3)

B = (-1,-5)

Required

Determine the coordinates of B'

Since A' is the image of A; we need to first calculate the scale factor using

A' = A * Scale\ factor

Make Scale Factor the subject

Scale\ Factor = \frac{A'}{A}

Substitute values for A' and A

Scale\ Factor = \frac{(-9,-3)}{(-3, -1)}

Factorize the numerator

Scale\ Factor = \frac{3 * (-3,-1)}{(-3, -1)}

Scale\ Factor = \frac{3 * 1}{1}

Scale\ Factor = 3

The coordinates of B' is then calculated as follows:

B' = B * Scale\ Factor

Substitute values for B and Scale Factor

B' = (-1,-5) * 3

B' = (-3, -15)

3 0
2 years ago
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