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Ghella [55]
3 years ago
11

Solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14

Mathematics
2 answers:
timurjin [86]3 years ago
6 0
What you have to do is solve for x of course stated above

4x - 2 + 5x + 10 = 2x +14 
9x +8 = 2x + 14
(minus 2x from both sides)
7x + 8 = 14
(minus 8 from both sides)
7x = 7
(divide 7 from both sides)
x=1
anastassius [24]3 years ago
4 0

Answer:

Its not one because 14-8 is not 7 its 6.

Step-by-step explanation:

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Step-by-step explanation:

NA = √[(- 4 - 1 )² + (- 3 - 2)²] = 5√2

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From (1) and (2) ⇒ NA║TS

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