Solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14

2 answers:

6 0

What you have to do is solve for x of course stated above

4x - 2 + 5x + 10 = 2x +14
9x +8 = 2x + 14
(minus 2x from both sides)
7x + 8 = 14
(minus 8 from both sides)
7x = 7
(divide 7 from both sides)
x=1

anastassius [24]3 years ago

4 0

Answer:

Its not one because 14-8 is not 7 its 6.

Step-by-step explanation:

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