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Charra [1.4K]
3 years ago
12

Ima post all my problems im sorry

Mathematics
2 answers:
sdas [7]3 years ago
8 0
Equalateral triangle
kotegsom [21]3 years ago
3 0
All the sides are of the same measure, therefore all the angles are also the same. The angle measure of a angle on an equilateral triangle is 60. This is because 180/3=60

60°
You might be interested in
What is the measure of x?<br> A.36<br> B.72<br> C.144<br> D.360
Helga [31]
We know that the interior angles of a trapezoid add up to 360 degrees. 

Write out an equation to represent this situation; 

108+108+2x+2x=360 
216+4x=360
4x=360-216 
4x=144 
x=144/4 
x=36 

Therefore, the measure of x is 36 degrees. 

Hope I helped :) 
4 0
3 years ago
(a) The weight of a package affects the cost to send that package through the mail.
skelet666 [1.2K]

Answer:

<u>cost to mail package</u>

Step-by-step explanation:

the weight is not dependant on the cost to mail the package

the cost depends on how much the package weighs.

7 0
3 years ago
if the statement “If i am hungry, then I am not happy” is assumed to be true, is its inverse, “ If i am not hungry, thrn i must
spayn [35]
Yes because "If i'm hungry, then I'm not happy" but "if I'm not hungry, then I'm happy"
Being hungry is bad, so I'm not happy
BUT
being not hungry is good, so I'm happy
3 0
4 years ago
Read 2 more answers
Lines I and m are parallel. If angle a
aliina [53]
C. 145°

Explanation:

angles A and D are opposite adjacent.
6 0
3 years ago
Left f(x)=x+1 and g(x)=1/x the graph of (f•g) (x) is shown below
Nikolay [14]

Answer:

Range of the function → (-∞, 1)∪(1, ∞)

Step-by-step explanation:

Two function has been given as,

f(x) = (x + 1)

and g(x) = \frac{1}{x}

Then (fog)(x) = f[g(x)]

Now f[g(x)] = \frac{1}{x}+1

As shown in the graph,

Domain of the graph is (-∞, 0) ∪ (0, ∞) [Since vertical asymptote of the function is x = 0, so x = 0 will not be included in the domain]

And the range is (-∞, 1) ∪ (1, ∞) [Since horizontal asymptote is y = 1, so y = 1 will not be included in the range]

4 0
4 years ago
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