Answer:
ΔH₁₂ = -867.2 Kj
Explanation:
Find enthalpy for 3H₂ + O₃ => 3H₂O given ...
2H₂ + O₂ => 2H₂O ΔH₁ = -483.6 Kj
3O₂ => 2O₃ ΔH₂ = + 284.6 Kj
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3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O (multiply by 3 to cancel O₂)
6H₂ + 3O₂ => 6H₂O ΔH₁ = 3(-483.6 Kj) = -1450.6Kj
2O₃ => 3O₂ ΔH₂ = -284.6Kj (reverse rxn to cancel O₂)
_______________________________
6H₂ + 2O₃ => 6H₂O ΔH₁₂ = -1735.2 Kj (Net Reaction - not reduced)
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divide by 2 => target equation (Net Reaction - reduced)
3H₂ + O₃ => 3H₂O ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj
Answer:
The pressure of the gas at 23 C is 179.92 kPa.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.
Gay-Lussac's law can be expressed mathematically as follows:

Studying two states, one initial 1 and the other final 2, it is satisfied:

In this case:
- P1= 310 kPa
- T1= 237 C= 510 K (being 0 C= 273 K)
- P2= ?
- T2= 23 C= 296 K
Replacing:

Solving:

P2= 179.92 kPa
<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>
Answer:
The correct answer is "more fluid bilayers".
Explanation:
A fatty acid is a biomolecule of lipidic nature formed by a long hydrocarbon chain of different lengths at the end of which there is a carboxyl group.
The wall of the gallbladder consists of three main layers of tissue: The mucosa covers the wall of the gallbladder. The muscular layer of smooth muscle. The serosa, which is the outer layer.
By decreasing the saturation of the fatty acid chains in phospholipids, the bile layers would reduce their thickness and become more fluid.
Have a nice day!
Answer:
the packing efficiency is 52.36%
Explanation:
Given the data in the question;
simple cubic unit cell that contains one atom with a metallic radius of 175 pm;
we know that;
Edge length of Simple cubic (a) is related to radius of atom (r) as follows;
a = 2r
since radius r = 175 pm
we substitute
a = 2 × 175 pm
a = 350 pm
Now we get the volume unit;
Volume of unit cell = a³ = ( 350 pm ) = 42875000 pm³
Next we get Volume of sphere;
Volume of Sphere =
πr³
Volume occupied by 1 atom =
× π × ( 175 pm )³
=
× π × 5359375 pm³
= 22449297.5 pm³
Now, the packing efficiency = ( Volume occupied by 1 atom / Volume of unit cell ) × 100
we substitute;
packing efficiency = ( 22449297.5 pm³ / 42875000 pm³ ) × 100
= 0.523598 × 100
= 52.36%
Therefore, the packing efficiency is 52.36%