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Fudgin [204]
3 years ago
13

How do you think this food web would be affected if the plants were eliminated

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
4 0
The Answer would be C. Without plants in the ecosystem, it could not feed. Plants are mainly the only producers that feed 3rd level consumers which feed 2nd level consumers which feed 1st level consumers.
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A student is asked to convert measurements from liters to milliliters and from milliliters to liters. His answers are shown in b
kirza4 [7]
The answer is 3.6L=360mL
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3 years ago
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Ayuda es urgente!! el tronco de madera y las cenizas pesan lo mismo ?​
skad [1K]

Answer:

Spanish

Explanation:

help is urgent the log of wood and the same

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2 years ago
Lysol Power Toilet Bowl Cleaner contains 9.5% hydrochloric acid. Explain why this would be necessary to clean toilet bowls that
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2 years ago
How many oxygen molecules are produced when 3.2×1022 molecules of water decompose?
snow_lady [41]
What this is confusing
8 0
3 years ago
Select the correct answer from each drop-down menu.
earnstyle [38]

Answer:

The granite block transferred <u>4080 joules</u> of energy, and the mass of the water is <u>35.84 grams</u>.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

<u>Part #1:</u>

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J                            c = 0.795 J/g°C

m = 126.1 g                     ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

<u>Part #2:</u>

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J                     c = 4.186 J/g°C

m = ? g                            ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

4 0
2 years ago
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