Answer:
See explanation
Explanation:
The elements in group form univalent positive ions and element in group 17 form univalent negative ions. Hence, when a group 1 element reacts with a group 17 element, a compound of the sort MX is formed. Hence, when a group 1 element reacts with bromine, a salt is formed with the general formula MBr.
Elements of group 1 are highly electro positive metals. They react with water to form the metal hydroxide and release hydrogen gas. Hence, when group 1 elements react with water, hydrogen gas is released.
A group 1 element forms a univalent positive ion while a group 16 element forms a divalent negative ion. Hence, when a groups 1 element reacts with oxygen, the compound formed must have the general formula M2O.
The reactivity of group 1 metal increases down the group hence Cs is the most reactive group 1 element.
Lithium displays a slightly different chemistry from other group 1 elements because of its small size.
A non-chlorine chemical such as iodine may be used as a
sanitizing solution. To use iodine as a sanitizing solution, it should be
around 12.5-25 ppm in water that is at least 75° F. Utensils and equipment must
be immersed for only 30 seconds because it may lose its effectivity if the pH
level gets too high due to high temperature. Discoloration may also result if
the utensils and equipment are in prolonged contact with the solution.
On the first one it is supposed to be 18. when you have a +1 charge you subtract it once. how i got 18 tho was from the protons. there was 19 so i subtracted that with 1 and got 18. hope that helped! :)
btw i’m not the best at explaining, i’m sorry :/
Answer:
Fe(NO3)3 + 3 NaOH ===》Fe(OH)3 + 3 NaNO3
Answer:
8.37 grams
Explanation:
The balanced chemical equation is:
C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)
Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.
From the ideal gas law we can determine the number of moles that the 2.25 L represent.
From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.
PV = nRT ⇒ n = PV/RT
n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂
Moles glucose required:
0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆
The molar mass of glucose is 180.16 g/mol, then the mass required is
0.046 mol x 180.16 g/mol = 8.37 g