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astraxan [27]
3 years ago
14

Answer this in your own words and I will mark brainlist ​

Chemistry
2 answers:
vova2212 [387]3 years ago
8 0

Answer:

hii i m here hope your day will energitic

san4es73 [151]3 years ago
4 0

Answer:

hlo please help me to do my question

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Explanation:

5 0
3 years ago
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VA 19.75-g sample was heated by 12.35 calories. The specific heat of the sample is 0.125 cal/g°C. What was the initial temperatu
SOVA2 [1]

Answer:

31.9 °C  

Explanation:

The formula for the heat q absorbed by an object is

q = mCΔT where ΔT = (T₂ - T₁)

Data:

q = 12.35 cal

m = 19.75 g

C = 0.125 cal°C⁻¹g⁻¹

T₂ = 37.0 °C

Calculations

(a) Calculate ΔT

q = mCΔT

12.35 cal = 19.25 g × 0.125 cal°C⁻¹g⁻¹ × ΔT

12.35 = 2.406ΔT °C⁻¹  

ΔT  = 12.35/(2.406 °C⁻¹) = 5.13 °C

(b) Calculate T₂

ΔT = T₂ - T₁

T₁ = T₂ - ΔT = 37.0 °C - 5.13 °C = 31.9 °C

The original temperature was 31.9 °C.

 

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3 years ago
What is the term for a bond composed of three electron pairs shared between two atoms?
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Answer B    only synthesis.

hope this helps!
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