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3 years ago

Which of the following statements about maintaining a fitness program is ture?

Chemistry

2 answers:

svp [43]3 years ago

5 0

Can u post the picture so i can answer it!

Ahat [919]3 years ago

4 0

Answer:

im sorry but you havent posted the pic

Explanation:

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A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric

Luba_88 [7]

Complete Question

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.

Answer:

The pressure required is $P_2= 12.2 \ atm$

Explanation:

Generally the volume of a sphere is mathematically denoted as

$V_s = \frac{4}{3} * \pi r^3$

Substituting $r = \frac{d}{2} = \frac{74}{2} = 37cm$

$V_s = \frac{4}{3} * 3.42 * (37)^2$

$V_s = 2.121746 *10^5 cm^3$

Converting to Liters

$V_s = \frac{2.121746 *10^5}{1000}$

$V_s= 212.1746L$

Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L

From Charles law

$P_1V_1 = P_2 V_s$

Substituting $V_1 =2600 L$ , $P_1 = 1 atm$ , $V_s =212.1746L$ , and making $P_2$ the subject we have

$P_2 = \frac{P_1 * V_1}{V_s}$

$= \frac{1 * 2600}{212.1746}$

$P_2= 12.2 atm$

6 0

3 years ago

HELPPP!!! What is the volume of a 1.31 moles sample of gas if the pressure is 904 mmHg and the temperature is 37. degrees Celsiu

Tju [1.3M]

Answer:

27.99 dm³

Explanation:

Applying

PV = nRT................ Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

From the question, we were aksed to find V.

Therefore we make V the subject of the equation

V = nRT/P................ Equation 2

Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

V = (1.31×310×0.082)/(1.1897)

V = 27.99 dm³

4 0

3 years ago

It is a large body of air that has the same properties as the Earth's surface over which it develops.what is it?

Debora [2.8K]

The answer is AIR MASS.

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3 years ago

Is a compound a mixture

Thepotemich [5.8K]

No, a compound is two elements that have been chemically combined to form something different. A mixture is two things that have been mixed together without creating a chemical change

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3 years ago

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The prefix centi- means

olya-2409 [2.1K]

100. Centi means a hundred.

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3 years ago

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