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allsm [11]
2 years ago
7

A gas cylinder contains exactly 1 mole of oxygen gas (O2). How many molecules of oxygen are in the cylinder? 4. 01 × 1022 molecu

les 6. 02 × 1023 molecules 9. 03 × 1024 molecules 2. 89 × 1026 molecules.
Chemistry
1 answer:
Over [174]2 years ago
5 0

The number of molecules on 1 mole of oxygen has been 6.023\;\times\;10^2^3 molecules. Thus, option B is correct.

The molecule has been the smallest unit of the compound. It has been the repeating unit to form the compound.

The molecule has been formed with the combination of the elements in the fixed proportion.

<h3>Number of molecules in a mole</h3>

The number of molecules in a mole of sample has been given by Avogadro's law. According to this, the number of molecules in a mole of sample has been equivalent to the Avogadro number.

The value of Avogadro number has been 6.023\;\times\;10^2^3.

Thus, the one mole of sample has been consisted of 6.023\;\times\;10^2^3 molecules.

The number of molecules on 1 mole of oxygen has been 6.023\;\times\;10^2^3 molecules. Thus, option B is correct.

Learn more about molecules, here:

brainly.com/question/19556990

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a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -&gt;<br> 4A1 + 302
Evgesh-ka [11]
<h3>Answer:</h3>

\displaystyle 40 \ mol \ Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 40 \ mol \ Al

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0
3 years ago
Please help its difficult
Likurg_2 [28]

Answer:

pounds

pounds pounds pounds

8 0
2 years ago
PLSSSSSSSS help !!!!! One mole of an element contains which of the following?
irina [24]

Answer:

6.02 × 10²³ atoms

Explanation:

The number 6.02 × 10²³ is called Avogadro number. It is the number of atoms,  ions and molecules in one gram atoms of an element, one gram ions of substance and one gram molecule of a compound.

For example:

32 g of oxygen = one mole = 6.02 × 10²³  atoms O.

1.008 g of hydrogen = one mole = 6.02 × 10²³  atoms of H.

or

18 g of H₂O =one mole = 6.02 × 10²³  molecules of H₂O

44 g of CO₂ = one mole = 6.02 × 10²³  molecules of CO₂

or

62 g of NO₃⁻ = one mole of NO₃⁻ = 6.02 × 10²³  ions of NO₃⁻

5 0
3 years ago
If a car jack's output force is 1000 N and the mechanical advantage is 6.8, what is the input force?
Travka [436]
Answer
147.06N
Explanation:
MA=Load/Effort
6.8=1000/x
Finding x you make x the subject and divide 1000 by 6.8 which is 147.06N
4 0
2 years ago
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