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3 years ago

Which object would have a mass of approximately 1,000 grams? A. book B. feather C. truck D. elephant

Mathematics

2 answers:

sp2606 [1]3 years ago

6 0

Answer is book.................

rusak2 [61]3 years ago

3 0

I hope this helps you

1000 mg=1 kg

it's might be book

feather <1 kg

truck>1 kg

elephant>1 kg

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A rectangular area adjacent to a river is fenced in; no fence is needed on the river side. The enclosed area is 1500 square fee

ZanzabumX [31]

Answer:

a) C(x) = 15000/x + 6x +80

b) Domain of C(x) { R x>0 }

Step-by-step explanation:

We have:

Enclosed area = 1500 ft² = x*y from which y = 1500 / x (a) where x is perpendicular to the river

Cost = cost of sides of fenced area perpendicular to the river + cost of side parallel to river + cost of 4 post then

Cost = 10*y + 2*3*x + 4*20 and accoding to (a) y = 1500/x

Then

C(x) = 10* ( 1500/x ) + 6*x + 80

C(x) = 15000/x + 6x +80

Domain of C(x) { R x>0 }

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2 years ago

Cell phone company A charges $20 per month plus $0.05 per text message. Cell phone company B charges $10 per month plus 0.07 per

balu736 [363]

Answer:

Yes, 500 texts.

Step-by-step explanation:

If you write out the equations, you can just set them up equal to each other and simplify.

A = .05x + 20

B = .07x + 10

.05x + 20 = .07x + 10 (subtract 10 from both sides)

.05x + 10 = .07x (subtract .05x from both sides)

10 = .02x (multiply both sides by 50

x = 500 texts

7 0

2 years ago

Which of the following represents the additive inverse of h?

erica [24]

Subtract ............

6 0

3 years ago

Read 2 more answers

A circle with a circumference of 51 inches to find the area

Kaylis [27]

$\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=51 \end{cases}\implies 51=2\pi r\implies \boxed{\cfrac{51}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \implies A=\pi \left( \cfrac{51}{2\pi } \right)^2\implies A=\cfrac{51^2}{2^2\pi }\implies A\approx 206.98$

4 0

2 years ago

Please help me!!!!! :)

dsp73

To find the volume,we would first need to find the height of square pyramid, by it's base edge and slant height using Pythagoras theorem:

${height }^{2} = {13}^{2} - {10}^{2} \\ {height }^{2} = 69 \\ height = \sqrt{69}$

We can then use the pyramid formula to find the volume:
$base \: \times \: height \: \times \frac{1}{3}$

In this case,the volume will be:

10×_/69×1/3
=27.68874...
≈27.7 units^3

Hope it helps!

5 0

3 years ago