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3 years ago

Solve these simultaneous equations Using the algerbraic method

1 answer:

4 0

The second equation equals: 3X +18y=60 (Both sides times 3)
And then use this new equation minus the first equation, you will get:
Left side: (3X +18y) - (<span>3x+6y)
Right side: 60-30
So 12y=30
Then y=2.5
Take y value into one of the three equations, you will get x=5

or

in another easier way:

Directly minus the second equation from the first one:
</span>(3x+6y) -(<span>X+6y)=10
</span>2X = 10
X = 5
Get Y is easy, Y=2.5

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Hannah received $30 for her birthday and bought 3 shirts that were all the same price. If she had $9 left over, which equation s

Natasha2012 [34]

Money spent + money left over = total money

money spent + 9 = 30

We don't know the price of each shirt, so let x = price of 1 shirt.
Then, 3 shirts cost 3 times as much as x, or 3x.
She spent 3x.

3x + 9 = 30

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2 years ago

Read 2 more answers

There are 176 freshmen and 18 adults, going on a trip to Great Adventure. The tickets are $60.00 for an individual or $300.00 fo

Iteru [2.4K]

Answer:

$5940

Step-by-step explanation:

19 groups = 19 x 300 = $5700

4 extra tickets = 4 x 60 = $240

$5700 + $240 = $5940

Total people going = 194

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2 years ago

Pam started watching a movie at 2:53 P.M. The movie was 1 hour and 52 minutes long. After the movie, Pam rode her bike for 46 mi

Karo-lina-s [1.5K]

The time Pam got home is 5:25 pm.

<h3>How to calculate time </h3>

Remember that 60 minutes is equivalent to 1 hour. When adding minutes together, when the minutes exceeds 60, convert to an hour.

<h3>How to determine the time Pam got home</h3>

In order to determine the time she got home, add the time she used to watch the movie , to the time she used to ride her bike home to the time the movie started.

2:53 + 1:52 + 46 = 5:25 pm

To learn more about addition, please check: brainly.com/question/19628082

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1 year ago

5x^2-5x-30=0 solve using quadratic

dangina [55]

Answer:

=−2

Step-by-step explanation:

4 0

2 years ago

Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to h

Anton [14]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The area of a regular octahedron is given by:

area = $2\sqrt{3}\ *edge^2$ . Let a is the length of the edge (diagonal).

area = $2\sqrt{3}\ *a^2$

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

$h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a$

The area of a tetrahedron is given by:

area = $\sqrt{3}\ *edge^2$ = $\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2$

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = $\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}$

7 0

3 years ago