Solve these simultaneous equations Using the algerbraic method

1 answer:

4 0

The second equation equals: 3X +18y=60 (Both sides times 3)
And then use this new equation minus the first equation, you will get:
Left side: (3X +18y) - (3x+6y)
Right side: 60-30
So 12y=30
Then y=2.5
Take y value into one of the three equations, you will get x=5

or

in another easier way:

Directly minus the second equation from the first one:
(3x+6y) -(X+6y)=10
2X = 10
X = 5
Get Y is easy, Y=2.5

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Definitions given.

Yuki888 [10]

The pitch of the roof is given by the ratio of the rise to the run of the roof, which is the slope of the rafter

$The \ pitch \ of \ the \ roof \ is \ \mathbf {\dfrac{6}{13}}$

Please find attached the simple diagram of the house with all measurements labeled

The reason the above value for the pitch and the diagram are correct are as follows:

The given parameters are;

Width of the section of the house on which the gable of the roof is to be placed = 50 feet

Length of the over hang on the sides of the roof = 1 foot each

Total span of the roof = 52 feet

Horizontal length of each rafter, the run = 26 feet

The height of the ridge above the top of the frame, the rise = 12 feet

Required:

To find the pitch of the roof

To draw a diagram of the house showing measurements

Solution:

$Pitch = \dfrac{Rise}{Run}$

$Pitch \ (slope) \ of \ roof = \dfrac{12}{26} =\dfrac{6}{13}$

Please find attached the diagram of the house showing the measurements for the roof parameters and the section of the house where the gable roof is to be placed

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