Solve these simultaneous equations Using the algerbraic method

1 answer:

4 0

The second equation equals: 3X +18y=60 (Both sides times 3)
And then use this new equation minus the first equation, you will get:
Left side: (3X +18y) - (3x+6y)
Right side: 60-30
So 12y=30
Then y=2.5
Take y value into one of the three equations, you will get x=5

or

in another easier way:

Directly minus the second equation from the first one:
(3x+6y) -(X+6y)=10
2X = 10
X = 5
Get Y is easy, Y=2.5

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The pair of values below is from a direct variation. Find the missing number.

NISA [10]

Answer:

The answer is 2.

2 since 6/4=3/2

Step-by-step explanation:

Since your relation is a direct variation then the points on your line are of the form y=kx where k is the constant of variation (also called constant of proportionality)

If y=kx then y/x=k.

So all the points in this relation since it is a direct variation will be equal to y-coordinate/x-coordinate.

So we are going to solve this proportion:

$\frac{6}{4}=\farc{3}{x}$

Again I put y/x from each point. They should have same ratio because this is a direct variation.

Cross multiply:

$6(x)=4(3)$

$6x=12$

Divide boht sides by 6:

$x=\frac{12}{6}$

$x=2$

6 0

3 years ago

Read 2 more answers

Answer the question.

san4es73 [151]

Alright so
5^4m = 5^12
cancel the bases
4m=12
divide by 4
m=3

6 0

3 years ago

At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad

sertanlavr [38]

Answer:

The length of the person’s shadow is 5.7ft

Explanation:

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the rules of trigonometry

$\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}$