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4 years ago

$700.19 rounded to the nearest $10

Mathematics

2 answers:

ololo11 [35]4 years ago

8 0

Answer:

$700

$700.19~$10= $700

Arada [10]4 years ago

8 0

700 $
Nearest 10$ means :
690$, 700$, 710$, etc…
In this case 700$ is the nearest

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Speedy Swift is a package delivery service that serves the greater Atlanta, Georgia, metropolitan area. To maintain customer loy

Paladinen [302]

Answer:

See Explanation and attachments

Step-by-step explanation:

Given

See question for data

Solving (a):

The scale used is an ordinal scale.

Ordinals scale uses hierarchy arrangement and the data can be arranged as:

$EARLY ->> ON-TIME ->> LATE ->> LOST$

The variable of the delivery performance is qualitative because it is non-numerical

Solving (b): Frequency table

From the table, we have:

$On - Time = 57$ $Early = 19$ $Late = 9$ $Lost = 2$

So, the frequency distribution table is:

$\begin{array}{cc}{Performance}&{Frequency}&{On-Time}&{57}&{Early}&{19}&{Late}&{9} & {Loss} & {2} & {Total} & {87}\end{array}$

Solving (c): Frequency table.

To do this, we add another column (Relative Frequency) to the above table.

The relative frequency is calculated as:

$Relative\ Frequency = \frac{Frequency}{Total}$

So, we have:

$On - Time = \frac{57}{87} = 0.656$ $Early = \frac{19}{87} = 0.218$

$Late = \frac{9}{87} = 0.103$ $Lost = \frac{2}{87} = 0.023$

So, the frequency distribution table is:

$\begin{array}{ccc}{Performance}&{Frequency}&{Relative\ Frequency} & {On-Time}&{57}&{0.656}&{Early}&{19}&{0.218} & {Late}&{9} & {0.103} & {Loss} & {2} & {0.023} & {Total} & {87}&{1}\end{array}$

Solving (d & e): See attachment 1 for bar chart & attachment 2 for pie chart

Solving (f):

From the question, we understand that the object is to return 99% early or on time and never to lose a package.

The analysis is as follows:

Early and On-Time (ET) packages

$ET = \frac{Early + On-Time}{Total} * 100\%$

$ET = \frac{57 + 19}{87} * 100\%$

$ET = \frac{76}{87} * 100\%$

$ET = \frac{7600}{87} \%$

$ET = 87.4 \%$

Lost packages

$Lost = \frac{Lost}{Total} * 100\%$

$Lost = \frac{2}{87} * 100\%$

$Lost = \frac{200}{87} \%$

$Lost = 2.30\%$

From the above analysis, we can see that 87.4% of the packages were delivered early enough and 2.30% were lost.

The fraction of packages delivered early can be improved and the fraction of lost packages can be reduced by exploring the chances of taking alternative routes when possible.

3 0

3 years ago

Taylor left to walk the dog at 4:25. She got back at 5:00. How long was the dog's walk?

Basile [38]

Answer:

Taylor walked 35 minutes

Step-by-step explanation:

4:25

+:35

=5:00.

once a clock hits 60 it's automatically turned to the next hour so since 25 + 35 = 50 it's automatically turned to 5:00

7 0

2 years ago

Solve for p.

Arte-miy333 [17]

2(p+1)=24
divide both sides by two
p+1=12
subtract 1 from both sides
p=11

4 0

4 years ago

Find the coordinates of P so that P partitions the segment AB in the ratio 6:2 if A(−4,12) and B(9,−4).

Jobisdone [24]

ANSWER

B. (5.75, 0)

EXPLANATION

If the point P(x,y) partitioned

$A(x_1,y_1)$

and

$B(x_2,y_2)$

in the ratio m:n, then

$x = \frac{mx_2+nx_1}{m + n}$

$y=\frac{my_2+ny_1}{m + n}$

If the coordinates are A(−4,12) and B(9,−4), then:

$x = \frac{6 \times 9+2 \times - 4}{6 + 2}$

$x = \frac{54 - 8}{8}$

$x = \frac{46}{8}$

$x = 5.75$

$y= \frac{6 \times - 4+2 \times 12}{6 + 2}$

$y = \frac{24 - 24}{8}$

$y = \frac{0}{24} = 0$

The correct choice is

$B. (5.75, 0)$

3 0

3 years ago

A dog sits at a corner of a square with side length 44 meters. the dog runs 10 meters along a diagonal toward the opposite corne

wlad13 [49]

Refer to the figure given below while reading the solution.

Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.

And then position B when traveled 5 m towards the right turning 90°.

We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).

Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).

Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.

The shortest distance of B from PQ = AC-AD
The shortest distance of B from SR = 44-(AC-AD)
The shortest distance of B from SP = AC+AD
The shortest distance of B from RQ = 44-(AC+AD)

So, the average of the shortest distances of B from each side is $\frac{(AC-AD)+44-(AC-AD)+(AC+AD)+44-(AC+AD)}{4}=\frac{44+44}{4}=22$

Hence, the average of the shortest distance of B from each side is 22 m

Learn more about average here-

brainly.com/question/24057012

#SPJ10

7 0

2 years ago