Question

Plz help me get the answer to these

Answer 1

- 9y - 4

factorise the numerator by taking out a common factor of 5y

45y² + 20y = 5y(9y + 4)

The expression now becomes

$\frac{5y(9y+4)}{-5y}$

the 5y on numerator/ denominator cancel leaving

- (9y + 4) = - 9y - 4 ← quotient

Answer 2

Answer:

-9y - 4

Step-by-step explanation:

$\dfrac{45y^2+20y}{-5y}=\dfrac{45y^2}{-5y}+\dfrac{20y}{-5y}=-9y-4$