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3 years ago

Help with homework q

Mathematics

1 answer:

garik1379 [7]3 years ago

6 0

Answer:

No mabey c

Step-by-step explanation:

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Olegator [25]

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3 years ago

(Find m∠IGH) m∠IGH =

Lina20 [59]

Answer:

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3 years ago

Find the area of the composite figure.

densk [106]

Answer:

100

Step-by-step explanation:

3 0

3 years ago

Marcus has earned 353 out of 400 points (88% or B+) in Math class. He needs 90% to earn an A-. There is one test left worth 100

aleksklad [387]

Answer:

Step-by-step explanation:

Marcus is aiming for an A- (90-94 percent). The question states that there is another test awaiting that is worth 100 points. In order to find the answer to the question, you need to:

1.) Add 400 + 100, to show how many points there are in total.

2.) Use the answer choices and add it to 353.

88 + 353 = 441

93 + 353 = 446

97 + 353 = 450

3.) Find the percentage of the sums.

441/500 = 88%

446/500 = 89%

450/500 = 90%

Since Marcus is aiming for an A-, we can conclude that obtaining 97 points will help Marcus achieve an A-.

8 0

2 years ago

Read 2 more answers

Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg

zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = average rent paid by 314 BYU students = $346

s = sample standard deviation = $86

n = sample of students = 314

$\mu$ = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, $\mu$ is ;

P(-2.082 < $t_3_1_3$ < 2.082) = 0.96

P(-2.082 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.082) = 0.96

P( $-2.082 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

P( $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

96% confidence interval for $\mu$ = [ $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $346 -2.082 \times {\frac{86}{\sqrt{314} } }$ , $346 +2.082 \times {\frac{86}{\sqrt{314} } }$ ]

= [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

5 0

3 years ago