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allochka39001 [22]
3 years ago
6

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
1 answer:
Alina [70]3 years ago
6 0

Yo sup??

We can solve this problem by applying trigonometric ratios.

sin36=XY/WY

WY=5/sin36

=8.5

Hope this helps.

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A flower bed has the shape of a rectangle 7 yards long and 3 yards wide. what is its area in square feet? be sure to include the
Nadusha1986 [10]
21 square yards. Length times width (7 times 3) equals 21
6 0
3 years ago
  PLZZZZZZZ HELPP  Which ordered pair is the solution to the system of equations? {y=2x−15} {4x+3y=−5} (5, −5) (4, −7) (0, 6) (7
Sophie [7]

solution is (4, - 7 )

given the equations

y = 2x - 15 → (1)

4x + 3y = - 5 → (2)

substitute y = 2x - 15 into (2)

4x + 3(2x - 15) = - 5

4x + 6x - 45 = - 5

10x - 45 = - 5 ( add 45 to both sides )

10x = 40 ( divide both sides by 10 )

x = 4

substitute x = 4 into (1) for corresponding value of y

y = (2 × 4 ) - 15 = 8 - 15 = - 7

solution is (4, - 7 )


8 0
3 years ago
What is the symbol for a segment bisector
lutik1710 [3]
This is the symbol for a segment bisector in geometry

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4 0
4 years ago
Which of the following statements are true of the graph of the function f(x)=(x+5)(x-3)?
mr_godi [17]

Answers: b, d and e

b.The graph has a relative minimum

d. The graph has an x intercept at 3,0

e. the graph has an y intercept at 0,-15

f(x)=(x+5)(x-3)

The given equation is in the form of f(x) = a(x-b)(x-c)

If 'a' is positive then graph has a relative minimum

If 'a' is negative then graph has a relative maximum

Here a=1 that is positive so graph has a relative minimum .

To find x intercept we set f(x) =0 and solve for x

0=(x+5)(x-3)

x+5 =0 -> x = -5 so x intercept is (-5,0)

x - 3=0 -> x= 3 so x intercept is (3,0)

To find y intercept we plug in 0 for x

y=(x+5)(x-3)

y=(0+5)(0-3) = -15

so y intercept is (0,-15)



5 0
3 years ago
Read 2 more answers
What angle has a tangent and sine that are both negative? <br><br> 300<br> 210 <br> 45 <br> 150
zimovet [89]

Answer:

300^{\circ}

Step-by-step explanation:

\text{In quadrant IV, both ratios of tangent and sine  are negative.}\\ \\300^{\circ}~ \text{lies in the fourth quadrant, so}~ \tan 300^{\circ}  ~ \text{and}~ \sin 300^{\circ}~ \text{are negative.}

6 0
2 years ago
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