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IgorLugansk [536]
3 years ago
13

432566 10.5.623467.14,5 4. What is the 1s (lower) quartile of the data set?

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

I feel sorry that looks hard. see how do you like it. waiting for an answer and then someone finally answers. and there being a smart Butt

Step-by-step explanation:

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Y = 8x + 6, x = 5 plz help i can get admin if i solve this
RoseWind [281]

Answer:

y = 46

Step-by-step explanation:

I'm assuming you wanted to solve for y.

x = 5

y = 8(5) + 6

y = 40 +6

y = 46

8 0
3 years ago
A snow plough has a 3.2m blade set at an angle of 30 degrees How wide a path will the snow plough clear
snow_tiger [21]

Answer:

1.6m

Step-by-step explanation:

The length of the blade is 3.2m

The angle which the blade makes is 30°

Assuming the path of the blade and the length it covers is a right-angled triangle,

The length of the blade is the hypothenus while the path at which it clears is the opposite of the triangle.

See attached document for better illustration.

Using SOHCAHTOA,

Sinθ = opposite / hypothenus

opposite = x

hypothenus = 3.2

θ = 30°

Sin30 = x / 3.2

X = 3.2sin30

X = 3.2 × 0.5

X = 1.6m

The path which the snow plough clears is 1.6m

6 0
3 years ago
Solve. 3(x-6)-2(2x+3)=14
coldgirl [10]

Answer:

x=-38

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)−2(2x+3)=14

(3)(x)+(3)(−6)+(−2)(2x)+(−2)(3)=14(Distribute)

3x+−18+−4x+−6=14

(3x+−4x)+(−18+−6)=14(Combine Like Terms)

−x+−24=14

−x−24=14

Step 2: Add 24 to both sides.

−x−24+24=14+24

−x=38

Step 3: Divide both sides by -1.

−x

−1

=

38

−1

x=−38

5 0
3 years ago
Read 2 more answers
Solve for angel GLN<br><br> please help asap, need help
likoan [24]

Answer:

119

Step-by-step explanation:

\mathrm{Supplementary\:angles\:add\:up\:to}\:180^{\circ }

\angle \:GKO \mathrm{\:is\:supplementary\:angle\:of\:} \angle \:KNL

\mathrm{So\:}\angle \:GKO+\angle \:KNL=180

\angle \:GKO+61=180

\angle \:GKO=119

6 0
3 years ago
Construct a frequency distribution and a frequency histogram for the data set using the indicated number of classes. Describe an
elena-s [515]

Answer and Explanation:

Number of classes = 8

    Highest value =2300

  Lowest value = 1250

Class width= highest value – lowest value / number of classes

               = 2300 – 1250/8

                = 131.25 = 132

So, we can write class as 1250+132=1382

Class                                        frequency

1250-1382                                 2

1382-1514                                 3

1514-1646                                 6

1646-1778                                 2

1778-1910                                 3

1910-2042                                 2

2042-2174                                 1

2174-2306                                 1

8 0
3 years ago
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