Answer:
umm i just woke up maybe later
Step-by-step explanation:
the first one is 6 red beads to 9 blue beads
the second one is 10 red beads to 15 blue beads
the last one is 14 red beads to 21 blue beads
hope this helps
Answer:
6 x 10^5
Step-by-step explanation:
7 x 10^6 is 7,000,000 and 6 x 10^5 is 600,000. The one that is closer is 6 x 10^5
Answer:
you must make an equation
Step-by-step explanation:
if you make an equation you should get the answer
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
Answer:
its 3.6
Step-by-step explanation: