-1/4 because you have to do ride over run which is y2-y1 divided by x2-x1. Then you get your answer.
This is how you set up a percent of error proportion:
<u>Amount of error</u> <u>x(Unknown percent)</u>
Actual value = 100(Percents are out of hundreds)
So if you fill it in, it becomes <u>4</u> <u>x
</u> 80 =100
Cross multiply, 400= 80x.
Solve.
x=5 so percent error is 5%<u>
</u>
Answer:
34 edges
Step-by-step explanation:
Euler's formula for polyhedron states
F + V - E = 2
where F is number of faces, V, number of vertices, E number of edges
Here F = 16, V = 20, thus
16 + 20 - E = 2, that is
36 - E = 2 ( subtract 36 from both sides )
- E = - 34 ( multiply both sides by - 1 )
E = 34
Yes of course because a shape is not nothing
![\bf \textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x) = 6.4\implies \log_{10}(x)=6.4\implies 10^{6.4}=x\implies 2511886.43\approx x](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%20%3D%206.4%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D6.4%5Cimplies%2010%5E%7B6.4%7D%3Dx%5Cimplies%202511886.43%5Capprox%20x)
let's recall that when the base is omitted, "10" is implied.
