Answer:
A) A(t) = 4500*π - 1600*t
B) A(4) = 7730 in³
C) t = 8,8 sec
Step-by-step explanation:
The volume of the sphere is:
d max = 30 r max = 15 in
V(s) = (4/3)*π*r³ V(s) = (4/3)*π* (15)³
V(s) = 4500*π
A) Amount of air needed to fill the ball A(t)
A(t) = Total max. volume of the sphere - rate of flux of air * time
A(t) = 4500*π - 1600*t in³
B) After 4 minutes
A(4) = 4500*π - 6400
A(4) = 14130 - 6400
A(4) = 7730 in³
C) A(t) = 4500*π - 1600*t
when A(t) = 0 the ball got its maximum volume then:
4500*π - 1600*t = 0
t = 14130/1600
t = 8,8 sec
35 pencils would cost $2.80,
$1.60 / 20 = $.08
Each pencil costs $0.08 each
.08 * 35 = 2.80
Up 2 units = y shifted up by 2:
y = x^2 + 2
to the right 3 units = x shifted right (+) by 3:
y + 3 = x^2 +2
new equation:
y = x^2 - 1
To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.
Prime factorization of 36=2×2×3×3
Prime factorization of 40=2×2×2×5
Prime factorization of 48=2×2×2×2×3
Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.
720seconds=
60
720
minutes=12minutes
Hence, all the bells will ring together after 12 mi
Answer:
The length of side of largest square is 15 inches
Step-by-step explanation:
The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.
Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.
So,
<u>Area of square 1: 81 square inches</u>
![s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9](https://tex.z-dn.net/?f=s%5E2%20%3D%20A%5C%5Cs%5E2%20%3D%2081%5C%5C%5Csqrt%7Bs%5E2%7D%20%3D%20%5Csqrt%7B81%7D%5C%5Cs%20%3D%209)
<u>Perimeter of square 2: 48 inches</u>
![4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches](https://tex.z-dn.net/?f=4%2Aside%20%3D%20P%5C%5C4%2A%20side%20%3D%2048%5C%5Cside%20%3D%20%5Cfrac%7B48%7D%7B4%7D%5C%5Cside%20%3D%2012%5C%20inches)
We can see that a right angled triangle is formed.
Here
Base = 12 inches
Perpendicular = 9 inches
And the side of largest square will be hypotenuse.
Pythagoras theorem can be used to find the length.
![(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15](https://tex.z-dn.net/?f=%28H%29%5E2%20%3D%20%28P%29%5E2%2B%28B%29%5E2%5C%5CH%5E2%20%3D%20%289%29%5E2%2B%2812%29%5E2%5C%5CH%5E2%20%3D%2081%2B144%5C%5CH%5E2%20%3D%20225%5C%5C%5Csqrt%7BH%5E2%7D%20%3D%20%5Csqrt%7B225%7D%5C%5CH%20%3D%2015)
Hence,
The length of side of largest square is 15 inches