Yearly budget= $26,760
Fixed expenses per month= $1340
Fixed expenses per year (1340×12) =$16,080
Living expenses per month= $850
Living expenses per year (850×12)= $10,200
Annual expenses= $60
Add ALL the expenses together.
16,080+10,200+60= £26340
Therefore her monthly budget is balanced. Shes not in deficit.
D
Answer & Step-by-step explanation:
In order to find the y-intercept of this equation, we must turn this equation into a slope-intercept equation. The equation for slope-intercept form is <em>y=mx+b. </em>We can do this by using these steps. Our goal is to get y by itself on one side.
6x - 2y - 9 = 0
Step 1: Add 9 on both sides of the equation.
6x - 2y = 9
Step 2: Subtract 6x on both sides of the equation. Once you subtract, make sure you put the -6x in front of 9 so we are following the rules of variables and exponents.
-2y = -6x + 9
Step 3: Divide -2 on both sides of the equation.
y = 3x - 
So, the y-intercept is -
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Answer:
to find the distance between two points on a coordinate plane
Step-by-step explanation:
yes
Answer:

Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:

where:


a=0

so the volume becomes:

This can be simplified to:

and the integral can be rewritten like this:

which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
]