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ololo11 [35]
3 years ago
5

abby went to the movies and buy a large container of popcorn. The popcorn container can be modeled by a right circular cone with

a diameter of 9 inches and a height of 10 inches. Popcorn has a density of 34 ounces per cubic foot. If a continer of popcorn costs $8, what is the price per ounce
Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0

Answer:

$1.918

Step-by-step explanation:

The volume of a right circular cone is obtained using the formular :

V = 1/3πr²h

From the question:

Diameter = 9 inches ; height = 10 inches

Radius = diameter /2 = 9/2 = 4.5 inches

V = 1/3*π*4.5²*10

V = 211.95 in³

Volume in ft³ = 211.95 / 1728 = 0.12265625 ft³

Density of popcorn = 34 ounces / ft³

Density of popcorn CONTAINER = x

1 ft³ = 34 ounce

0.12265625 ft³ = x

Cross multiply

x = 34 * 0.12265625 ft³

x = 4.1703125 ounce

Hence, popcorn continer has a density of 4.1703125 ounce

If price per container = $8

The price per ounce = $8 / 4.1703125

= $1.918

Hence, price per ounce is $1.918

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Gianna put $1000 in a savings account for 18 months, The interest on the account is 3.5%. How much will Gianna earn in interest?
zimovet [89]

Answer:

amount of interest = 52.5

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Step-by-step explanation:

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PRT/100

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T is the Time taken

18 months  = 1 years 6 months ( 1.5 years)

1000 * 3.5 * 1.5 = 5250

5250/100 = 52.5

the amount of interest = <u>52.5</u>

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With a height of 68 ​in, Nelson was the shortest president of a particular club in the past century. The club presidents of the
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Answer:

a. The positive difference between Nelson's height and the population mean is: \\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in.

b. The difference found in part (a) is 1.174 standard deviations from the mean (without taking into account if the height is above or below the mean).

c. Nelson's z-score: \\ z = -1.1739 \approx -1.174 (Nelson's height is <em>below</em> the population's mean 1.174 standard deviations units).

d. Nelson's height is <em>usual</em> since \\ -2 < -1.174 < 2.

Step-by-step explanation:

The key concept to answer this question is the z-score. A <em>z-score</em> "tells us" the distance from the population's mean of a raw score in <em>standard deviation</em> units. A <em>positive value</em> for a z-score indicates that the raw score is <em>above</em> the population mean, whereas a <em>negative value</em> tells us that the raw score is <em>below</em> the population mean. The formula to obtain this <em>z-score</em> is as follows:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

\\ z is the <em>z-score</em>.

\\ \mu is the <em>population mean</em>.

\\ \sigma is the <em>population standard deviation</em>.

From the question, we have that:

  • Nelson's height is 68 in. In this case, the raw score is 68 in \\ x = 68 in.
  • \\ \mu = 70.7in.
  • \\ \sigma = 2.3in.

With all this information, we are ready to answer the next questions:

a. What is the positive difference between Nelson​'s height and the​ mean?

The positive difference between Nelson's height and the population mean is (taking the absolute value for this difference):

\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in.

That is, <em>the positive difference is 2.7 in</em>.

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To find how many <em>standard deviations</em> is that, we need to divide that difference by the <em>population standard deviation</em>. That is:

\\ \frac{2.7\;in}{2.3\;in} \approx 1.1739 \approx 1.174

In words, the difference found in part (a) is 1.174 <em>standard deviations</em> from the mean. Notice that we are not taking into account here if the raw score, <em>x,</em> is <em>below</em> or <em>above</em> the mean.

c. Convert Nelson​'s height to a z score.

Using formula [1], we have

\\ z = \frac{x - \mu}{\sigma}

\\ z = \frac{68\;in - 70.7\;in}{2.3\;in}

\\ z = \frac{-2.7\;in}{2.3\;in}

\\ z = -1.1739 \approx -1.174

This z-score "tells us" that Nelson's height is <em>1.174 standard deviations</em> <em>below</em> the population mean (notice the negative symbol in the above result), i.e., Nelson's height is <em>below</em> the mean for heights in the club presidents of the past century 1.174 standard deviations units.

d. If we consider​ "usual" heights to be those that convert to z scores between minus2 and​ 2, is Nelson​'s height usual or​ unusual?

Carefully looking at Nelson's height, we notice that it is between those z-scores, because:

\\ -2 < z_{Nelson} < 2

\\ -2 < -1.174 < 2

Then, Nelson's height is <em>usual</em> according to that statement.  

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