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2 years ago

How do you solve m/9 divided by mn squared / 3

Mathematics

2 answers:

ivolga24 [154]2 years ago

3 0

$\frac{m}{9}:\frac{mn^2}{3} =\frac{m}{9} \cdot \frac{3}{mn^2} =\frac{1}{3n^2}$

katovenus [111]2 years ago

3 0

$To\ divide\ fraction\ multiply\ first\ fraction\ by\ inverse\ of\ the\ second:\\\\ \frac{m}{9}:\frac{mn^2}{3}=\frac{m}{9}*\frac{3}{mn^2}=\frac{1}{3n^2}
\\\\Solution\ is \ \frac{1}{3n^2}.$

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Answer:

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Step-by-step explanation:

Let

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$0.50x+1y=80$ (Hot dogs were sold for $.50 (fifty cents), and hamburgers were sold for $1 (one dollar). The total money raised by your class was $80. )

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Subtract both equations to get value of x:

$0.50x+y=80\\x\:\:\:\:\:\:\:\: + y=108\\-\:\:\:\:\:\:\:\: -\:\:\:\:\:\: -\\---------\\-0.5x=-28\\x=\frac{-28}{-0.5}\\x=56$

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