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3 years ago

Suppose the total cost for n tickets is $36 what's is the total cost of one more ticket is purchased

1 answer:

7 0

$36/n because since there are n amount of tickets, you should divide $36 by n. I feel like you won't get me. For instance, let's say n is 6 tickets. So if 6 tickets are for $36, you should divide $36 by 6 tickets to find the unit rate. Hope this helps.

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Below is the number of service calls a store received over a period of 87 days.

oksian1 [2.3K]

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4 0

2 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2

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brainly.com/question/1962726

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5 0

1 year ago

Please help me on this it’s due now

Black_prince [1.1K]

Answer:

I don't understand the question

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2 years ago

A circle representing a pool is graphed with a center at the origin. Grant enters the pool at point A and swims over to a friend

stich3 [128]

Answer:

4-x/2

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

BRAINLIEST 60 POINTS!! PLEASE HELP ITS DUE TODAY

yKpoI14uk [10]

Answer:

1. $x^\circ= 7^\circ$

2.(a)Therefore , Side LJ =side CA

(b) BC = KL

Step-by-step explanation:

we know that, vertically opposite angles are congruent .

$\therefore (x+16)^\circ= (4x-5)^\circ$

$\Leftrightarrow 4x^\circ-x^\circ= 5^\circ+16^\circ$

$\Leftrightarrow 3x^\circ= 21^\circ$

$\Leftrightarrow x^\circ= 7^\circ$

(a)SAS = side,angle , side

Given ,side AB = side KJ

and ∠CAB= ∠LJK

All Pythagorean Triples are unique.

Since side AB = side KJ

Therefore , Side LJ =side CA

It satisfies SAS postulate ThereforeΔABC≅ΔKJL

(b)

HL Theorem: If hypotenuse and one leg of of a right triangle are congruent to the hypotenuse and one leg of of other right triangle , then the triangle congruent.

Since,

All Pythagorean Triples are unique.

Then hypotenuse of ΔABC=ΔLKJ ⇔BC = KL

8 0

3 years ago