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viva [34]
3 years ago
15

Today i will walk 3 miles per hour to school, which is 1.5 miles away how many hours would this trip take

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
7 0

Answer:

2 hours

Step-by-step explanation:

divide3 by 1.5 and that is how long it will take you

GaryK [48]3 years ago
4 0

Answer: 30 minutes so 1/2 hour

Step-by-step explanation:

Because 3 miles = 1 hour

1.5 times 2 = 3

divide 2 on both sides

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Two mechanics worked on a car. The first mechanic charged S95 per hour, and the second mechanic charged S115 per hour.
Norma-Jean [14]

The first mechanic worked for 10 hours and the second mechanic worked for 15 hours.

Step-by-step explanation:

Given,

Charges of first mechanic = $95 per hour

Charges of second mechanic = $115 per hour

Total hours = 25

Total amount charged = $2675

Let,

The number of hours worked by first mechanic = x

The number of hours worked by second mechanic = y

According to given statement;

x+y=25    Eqn 1

95x+115y=2675     Eqn 2

Multiplying Eqn 1 by 95

95(x+y=25)\\95x+95y=2375\ \ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(95x+115y)-(95x+95y)=2675-2375\\95x+115y-95x-95y=300\\20y=300

Dividing both sides by 20

\frac{20y}{20}=\frac{300}{20}\\y=15

Putting y=15 in Eqn 1

x+15=25\\x=25-15\\x=10

The first mechanic worked for 10 hours and the second mechanic worked for 15 hours.

Keywords: linear equation, elimination method

Learn more about elimination method at:

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lana66690 [7]

He sold 76 shirts and 24 pants.

Step-by-step explanation:

Given,

Cost of one t-shirt = $20

Cost of one pants = $45

Total items sold = 100

Total sales = 2600

Let,

x be the number of t-shirts

y be the number of pants

According to given statement;

x+y=100    Eqn 1

20x+45y=2600   Eqn 2

Multiplying Eqn 1 by 20

20(x+y=100)\\20x+20y=2000\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(20x+45y)-(20x+20y)=2600-2000\\20x+45y-20x-20y=600\\25y=600

Dividing both sides by 25

\frac{25y}{25}=\frac{600}{25}\\y=24

Putting in Eqn 1

x+24=100\\x=100-24\\x=76

He sold 76 shirts and 24 pants.

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