Question

Which equation represents a line that passes through (4,1/3 ) and has a slope of 3/4?

Answer 1

For this case we have that by definition, the slope-intersection equation of a line is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut point with the y axis.

They tell us as data that:

$m = \frac {3} {4}$

Now the equation is:

$y = \frac {3} {4} x + b$

We substitute the point to find "b":

$(4, \frac {1} {3})$

$\frac {1} {3} = \frac {3} {4} (4) + b$

$b = \frac {1} {3} -3\\b = - \frac {8} {3}$

Finally the equation is:

$y = \frac {3} {4}x - \frac {8} {3}$

In point-slope form the equation is:

$y- \frac {1} {3} = \frac {3} {4} (x-4)$

Answer:

$y = \frac {3} {4}x - \frac {8} {3}$

Answer 2

Answer:

y - 1/3 = 3/4(x - 4)

Step-by-step explanation:

We know that the general equation of a line is the following:

y - yo = m(x-xo), where 'm' represents the slope of the line, and (xo, yo) is any point that belongs to the line.

Then, the equation of the line that passes through (4, 1/3) and has a slope of 3/4 is: y - 1/3 = 3/4(x - 4)