The weight gets transferred through the members to the supports and back to the ground
It is africa hope this helps
Answer:
Indo-European, Germanic, English, Midland-Northern
Explanation:
Answer: The answer is: f(x) = 2x^2 + 40x + 200
Explanation:
Given: x is the width of the Artwork
Let W be the Width of the Frame
Let L be the Length of the Frame
Width = x + 10
Length = Width * 2, so by substitution, Length = 2(x + 10)
Area = Width * Length
By substitution:
Area = (x + 10) * 2(x + 10)
f(x) = (x + 10) * (2x + 20)
f(x) = 2x^2 + 20x + 20x + 200
f(x) = 2x^2 + 40x + 200
To test this, if a picture 8" wide is put in this frame, the width would be 8+10 or 18 inches. The length would be twice the width, or 36 inches. The Area is 18 x 36 = 648.
Using the formula:
f(8) = (2 * 8^2) + (40 * 8) + 200
f(8) = (2 * 64) + 320 + 200
f(8) = 128 + 320 + 200
f(8) = 648
1st, let's calculate the side AB = c in applying the law of cosine:
AC² = BC²+AC² - 2AB.BC. cos87°)
c²= 10.1²+9.8²-2(10.1)(9.8)(cos(87)
c²=102.01 + 96.04 -196.96cos(87)
c² = 187.74 and c = 13.7
Having calculated the 3rd side, now we can apply Heron's formula for the area:
AREA = √p(p-a)(p-b)(p-c), where p is half the perimeter or p=(a+b+c)/2 =16.8
AREA = √16.8(16.8-10.1)(16.8-9.8)(16.8-13.7)
AREA = 49.42 OR 49.4 unit²
