It must exceed seven. x < 7 x ≤ 7 x > 7 x ≥ 7
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Let the kite is the quadrilateral ABCD with the two pairs of adjacent congruent sides. (the diagram is also attached)
<span>Now, its given in question, see from figure,
AB is congruent to AD </span>
BC is congruent to DC
Now, let us join the points A & C to form AC ; and points B and D to form BD.
So, AC is common side to triangles ABC and ADC.
So, Because AB ≈AD
BC ≈ DC
And, AC is common, therefore,
<span>triangle ABC is congruent to triangle ADC
</span>
⇒∠ ABC ≈ ∠ADC (These are the angles between the non-congruent sides)
<span>Now, its given in question, see from figure,
AB is congruent to AD </span>
BC is congruent to DC
Now, let us join the points A & C to form AC ; and points B and D to form BD.
So, AC is common side to triangles ABC and ADC.
So, Because AB ≈AD
BC ≈ DC
And, AC is common, therefore,
<span>triangle ABC is congruent to triangle ADC
</span>
⇒∠ ABC ≈ ∠ADC (These are the angles between the non-congruent sides)