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svetoff [14.1K]
3 years ago
10

The directions for a jewelry-making pattern call for a chain 358 inches long. When shopping for a chain, the following choices w

ere available. What is the correct length for the pattern?
Mathematics
2 answers:
lana [24]3 years ago
5 0

3.625 inches

Answer

kobusy [5.1K]3 years ago
4 0

Answer:

the correct pattern is 400 inches long

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I hope it’s clear enough but can some please help
Liula [17]

Answer:

b

Step-by-step explanation:

hope this helps you! have a good day!

6 0
3 years ago
#11 (Angles with Equations) In the figure below, 2POR is 180°.
lina2011 [118]

Answer:

55

Step-by-step explanation:

The three angles form a straight line, so they add to 180.

x + x + 70 = 180

Combine like terms

2x+70 =180

Subtract 70 from each side

2x+70-70 =180-70

2x= 110

Divide by 2

x = 55

SQT = x

So SQT = 55

4 0
3 years ago
A 12-ft ladder is placed 5 feet from a building. Approximately how high does the ladder reach?
ElenaW [278]
If your adding its 17, Subtracting its 7, multiplying its 60 and dividing its 2.4 hope this helps
4 0
3 years ago
The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims
kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is \mu=600, we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it \sigma) is

\sigma=48

Next they draw a random sample of n=70 students, and they got a mean score (denoted by \bar x) of \bar x=613

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis H_0:\bar x \geq \mu

- The alternative would be then the opposite H_0:\bar x < \mu

The test statistic for this type of test takes the form

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\

<h3>since 2.266>1.645 we  can reject the null hypothesis.</h3>
6 0
3 years ago
Read 2 more answers
I need help on this please
ss7ja [257]

Answer:D

Step-by-step explanation:

.708333... so about .71

14+23+14=51

51 divided by 72=~.71

6 0
3 years ago
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