<span>f(x) = x^2 - 12x + 7
First, separate the first two terms from the constant
f(x) = (x^2 - 12x) + 7
Next, half the coefficient of second term in the parenthesis (12x) and square the result. Make sure to subtract outside the parenthesis what you added inside so that the equation stays equal.
f(x) = (x^2 - 12x + 36) + 7 - 36
f(x) = </span><span>(x^2 - 12x + 36) - 29
Now, just factor the trinomial inside the parenthesis, lemme know in a comment if you don't know how to do this and I'll explain.
f(x) = (x(x - 6) -6(x - 6)) - 29
f(x) = (x - 6)^2 - 29
The polynomial is now in vertex form, and the value of a, as you can see, is 6.
</span>
It is 5 becuase 5 times 1 is 5
Answer:
The answer is A) -17 + 2x
Step-by-step explanation:
You can just swap the factors to get an equivalent expression.
If you swap 2x and -17 you get -17 + 2x which is equivalent to the original expression therefore that is your answer
If I'm reading this copy-pasted math right, you have 
parameterized by
with 
. Then
so that
Answer:
The correct option is;
D) Neither the domain restriction nor the expression for f⁻¹(x) is correct
Step-by-step explanation:
The given function can be written as follows;
f(x) = x² - 331
The inverse of the function f(x), which is f⁻¹(x), can be found as follows;
Let f(x) = x² - 331 = y, we have;
f(x) + 331 = x²
x = √(f(x) + 331)
We replace x with f⁻¹(x) and f(x) with x, to get;
f⁻¹(x) = √(x + 331)
We note that the domain of the inverse function will include values from x ≥ -331, and the correct inverse function √(x + 331) ≠ √x - 331
Therefore, we have that neither the domain restriction nor the expression for f⁻¹(x) is correct.
