What is the largest decimal value you can represent, using a 86-bit signed integer?
1 answer:
Answer:
Explanation:
Considering the number are stored using binary notations.
If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have bit combinations since a bit can be either stored as 0 or as 1.
Therefore, the largest number that can be stored will be .
To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to .
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Answer:
Explanation:
The following is written in Java. It creates the function num_eights and uses recursion to check how many times the digit 8 appears in the number passed as an argument. A test case has been created in the main method and the output can be seen in the image below highlighted in red.
public static int num_eights(int pos){
if (pos == 0)
return 0;
if (pos % 10 == 8)
return 1 + num_eights(pos / 10);
else
return num_eights(pos / 10);
}
