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solong [7]
3 years ago
9

Kiara is using her software's graphic formats to create a line graph. As she

Computers and Technology
2 answers:
rewona [7]3 years ago
8 0

Answer:

Correct the data she entered, and the software will adjust the  graph.

Explanation:

Software is used to work with ease and efficiency. If there is any mistake during data entry, we can easily change that particular data and make it correct. There is no need to delete whole data and re enter the data again. As most of the software are user friendly and have the option to edit the information that already has been entered.

In mentioned case, Kiara should edit the data, that has been entered incorrect. After the correction of data, the graph will be automatically updated with new values and she found correct graph.

11111nata11111 [884]3 years ago
4 0

Answer:

D. Correct the data she entered, and the software will adjust the graph.

Explanation:

I just got this answer correct on an Apex quiz, I hope this helps!

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WILL GIVE BRAINLIEST!!!!!!!!!
sukhopar [10]

Answer:

True

Explanation:

7 0
3 years ago
A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on average once every 100 sec, e
Sunny_sXe [5.5K]

Explanation:

Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184

Then, the stations N share 56 kbps

And, the channel rate = 0.184*56 = 10.304 kbps.  

Then, the outputs of the wach stations is 1000-bit frames/100 sec

\therefore, the output of the bits/ sec by each stations = \frac{1000}{100} bits/sec = 10 bits/sec

So, The output of the N stations is 10 bits/sec on the channel that having 10.304kb/sec

Finally, N = \frac{(10.304 \times 10^{3})}{10} = 1030 stations

3 0
3 years ago
Assume the system with 256B memory and 64B cache and the block size of 16 bytes. I.e., there are 4 blocks in the cache. (a) For
Nataliya [291]

Answer:

Check the explanation

Explanation:

1.

System = 256Byte = 8 bit

Cache = 64B , block size = 16 byte.

A) Direct Mapped Cache:

Block offset = log (Block size) = log 16 = 4bit

Total # of block inside cache = 4.

Therefore index offset = log 4 = 2bit.

Remaining is tag bits.

Therefore tag bits = 8-(4+2) = 8-6 = 2 bits

Tag                              Index offset                                Block offset

(2 bits)                             (2 bits)                                           (4 bits)

Fully associative cache :

In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.

Therefore tag bits = 8-block offset bit= 8-4 =4bits

Tag                               Block offset

(4 bits)                                (4 bits)

4 0
3 years ago
Sharon is responsible for the security on web applications. She’s looking to see if all applications have input validation. What
LiRa [457]

Answer:

Options Include:

<em>A) Server-side validation </em>

<em>B) Client-side validation </em>

<em>C) Validate in trust </em>

D) Client-side and server-side validation

<em>Client-side and server-side validation is Correct</em>

Explanation:

The best option is to validate the client side with the server side. Using these together would provide the best testing option for Sharon.

<em>This keeps user feedback instantly without wasting postbacks while also protecting against JavaScript disabled users. That's how the validation controls for ASP.NET operate. </em>

This is definitely not over-engineering as there are risks of using one without the other.

Individual validation on the server side and individual validation on the client side are both incorrect. Trust validation is not a form of validation.

4 0
3 years ago
What does a computer monitor look like when struck really hard?
sveticcg [70]

Answer:

physical damage could include broken glass or ink splotches on the display, distorted images, or discoloration

5 0
2 years ago
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