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oksian1 [2.3K]
3 years ago
12

Help 30 point question!

Mathematics
1 answer:
Gennadij [26K]3 years ago
4 0

You're given 3 points (<em>x</em>, <em>y</em>) on the circle with equation

<em>x</em> ² + <em>y</em> ² + <em>Dx</em> + <em>Ey</em> + <em>F</em> = 0

and you have to use these known points on set up 3 equations involving <em>D</em>, <em>E</em>, and <em>F</em>.

For the point (3, -1), this means when <em>x</em> = 3, <em>y</em> = -1, so

3² + (-1)² + 3<em>D</em> - <em>E</em> + <em>F</em> = 0

→   3<em>D</em> + (-1)<em>E</em> + 1<em>F</em> = -10

The next point (-2, 4) gives

(-2)² + 4² - 2<em>D</em> + 4<em>E</em> + <em>F</em> = 0

→   (-2)<em>D</em> + 4<em>E</em> + 1<em>F</em> = -20

And from the last point (6, 8),

6² + 8² + 6<em>D</em> + 8<em>E</em> + <em>F</em> = 0

→   6<em>D</em> + 8<em>E</em> + 1<em>F</em> = -100

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5 0
3 years ago
The figure is made up of a hemisphere and a cylinder.
Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
V = 8*3.14*5^2
V = 8*3.14*25
\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}
V =  \frac{1570}{6}
\boxed{V_{hemisphere}\approx 261.6\:cm^3}


<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
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Hello,
H^(-1)(x)=-3/2 x+9
Answer A
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Answer:

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Step-by-step explanation:

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