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Nezavi [6.7K]
3 years ago
6

I need this simplify ratios: fractions​

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

20 : 9

Step-by-step explanation:

Given the ratio

2 : \frac{9}{10}

Multiply both parts of the ratio by 10 to clear the fraction

= 20 : 9

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Match each point with one of the following fractions: 5/6, 7/12, 1/8, 5/16
Anton [14]
Answer is B. second one

A = 1/8, B = 5/16, C = 7/12, D = 5/6
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6 0
3 years ago
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What is i^30?<br>0A. -i<br>0B. -1<br>0C. 1<br>0D. i​
kozerog [31]

Answer:   B

Step-by-step explanation:

-1 will be your answer. (B)

6 0
3 years ago
David hikes 2 ¼ miles in ½ an hour at this rate, how long will it take him to walk 18 miles?
8090 [49]
So in 30 min will hike 2 1/4 miles =9 of those 1/4 miles therefore in 10 min will hike 9/3 =3 of those 1/4 miles = 3/4 of a mile

3/4 mile in 10 min;
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6 miles in 80 min;
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12 miles in 160 min;
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5 0
3 years ago
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
2 years ago
A random sample is made of 256 middle managers concerning their annual incomes. The sample mean is computed to be $35,420. If th
ziro4ka [17]

Answer: a. $128.125

Step-by-step explanation:

The standard error of the mean is given by :

SE=\dfrac{\sigma}{\sqrt{n}} , where \sigma = population standard deviation , n= sample size.

Given: \sigma=\$2,050

n= 256

Then, the standard error of the mean:-

SE=\dfrac{2050}{\sqrt{256}}\\\\=\dfrac{2050}{16}=\$128.125

Hence, option a. is correct.

3 0
3 years ago
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