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vodomira [7]
3 years ago
13

Change 7 3/8 from a mixed. number to to an improper fraction

Mathematics
2 answers:
ASHA 777 [7]3 years ago
7 0
First, we set up the mixed number 7 3/8 with different colors, so it is easy to follow along:

7
3
8

Step 2 - Multiply
Next, we multiply the whole number by the denominator.

7 x 8 = 56

Step 3 - Add Numerator
Then, we add the numerator to the answer we got in Step 2.

56 + 3 = 59

Step 4 - Solution
Finally, to get the solution, we keep the original denominator and make the numerator the answer from Step 3. Thus, 7 3/8 as an improper fraction is:

59
8
mote1985 [20]3 years ago
7 0

Answer:

59/8

Step-by-step explanation:

Multiply the whole number by the denominator.

7 * 8 = 56

Add the numerator to the product.

56 + 3 = 59

Write the sum over the denominator.

\boxed{\frac{59}{8}}

Hope this helps.

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Answer:

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Step-by-step explanation:

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The 3x falls under 90 degrees.

So:

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2 years ago
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You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
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Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

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The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

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The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

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\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

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For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

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