Question

Given a term and the common ratio of a geometric sequence find the first five terms and

Answer 1

Answer:

$a_{n} = -16/27(2/3)^{n-1}$

Step-by-step explanation:

Given :-

a₅ = -16/27

r = 2/3

To Find :-

nth term

Solving :-

a₅ = ar⁴ = -16/27

a = -16/27 x (3/2)⁴

= -16/27 x 81/16

= -3

Solution :-

$a_{n} = -16/27(2/3)^{n-1}$