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3 years ago

Help please. It's be thanks.

Mathematics

1 answer:

inessss [21]3 years ago

7 0

Answer:

your answer is choice a

Step-by-step explanation:

because the one line passes the x-axis at -3.5 and the other line crosses the x-axis at 3. then you have another line that crosses the y-axis at 2

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Please help!!! I have a chance to get $50 if I get all of these questions right!!

AnnyKZ [126]

Answer:

number 1 is c number 2 is b,c,e number 3 is b

Step-by-step explanation:

1: if you see something to the power you will always think of repeated multiplication off the bat. so you just multiply the coefficient by the amount of the exponent.

2: 1*1*1*1*1*1*1*1*1*1*1*1*1*1*1*1=1 no

2*2*2*2=16 yes

4*4=16 yes

8*8=64 no

16=16 yes

3: 3/4*3/4*3/4=27/64

hope this helps! have a nice day!

3 0

2 years ago

What is another expression that is equivalent to 12-16x

sergij07 [2.7K]

4(3-4x) . This is solved by factoring a 4 out of the equation. Distributing the 4 in the answer will provide the same equation as the one questioned.

5 0

2 years ago

a store sells small notebooks for $7 and large notebooks for $14. if a student buys 6 note books for $63, how many notebooks eac

bija089 [108]

The answer is 3 of each. 3X7=21; 14X3=42, and 42+21= 63.

4 0

3 years ago

Read 2 more answers

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

2 years ago

Mr. Smith decided to regularly wash his head with an antidandruff shampoo every three days. He began on January 1st, 2017 on Sat

mezya [45]

Answer:

If the first day is January 1st, 2017 on a "sunday"(Not saturday), that means that the last day is December 31, 2017 on a sunday. (Pog moment for mee)

Step-by-step explanation:

3 0

2 years ago

Help please. It's be thanks. ​

Help please. It's be thanks.