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Black_prince [1.1K]
3 years ago
8

Point W ____ is on segment AB so that AW= 1/5AB

Mathematics
1 answer:
sattari [20]3 years ago
3 0
The answer is 1.3.4
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a hotel has a number of meeting rooms,m, available for events. each meeting room has 325 chairs. write an equation to represent
liq [111]
C=325m
Because for every meeting room there is 325 chairs and c=the total of chairs
6 0
3 years ago
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0
3 years ago
5 thank you so much!!!
Usimov [2.4K]

Answer:

all work is shown and pictured

4 0
3 years ago
Divide three fourths ÷ two fifths
KengaRu [80]
Your answer would be on eof the three
15/8
1.875
1 7/8
Hope this helps...
7 0
3 years ago
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a soup can that is a cylinder has a radius of 2x-1 and a height of 3x. what is the surface area of the soup can? show your work
valentinak56 [21]
The Surface Area is 62.83185 m²
5 0
3 years ago
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