Answer:
12.0415945788
Step-by-step explanation:
Answer;
C) The second arc should be centered at C.
Explanation;
Assuming the goal is to construct a line parallel to AB that passes through given point C.
-Draw a line through C and across AB at an angle creating D.
- With the compass width about half of DC, and center D, draw the first arc to cross both lines.
-Using the same compass width , draw the second arc with center C.
-Then set the compass width to the lower arc (the first arc)
- Move the compass to the second arc. Mark off an arc to make point E
-Draw a straight line through C and E
Thus the line CE will be parallel to line AB
Answer:
f(x)=x-2
Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.
Domain: (−∞,∞),x|x ∈R}(-∞,∞),{x|x ∈R}
Range: (−∞,∞),{y|y∈R}
g(x)=x^2-3x+2
Domain: (−∞,∞),{x|x ∈R}(-∞,∞),{x|x ∈R}
Range: [−1/4,∞),{y∣y≥−1/4}
Answer:
3) Midpoint is (-4,0.5)
Option A is correct.
4) Midpoint is (2.5,0)
Option B is correct.
5) The factors are (x+4)(x-7)
Option C is correct.
6) The factors are (x+4)(x+2)
Option A is correct.
Step-by-step explanation:
Question 3
Find midpoint of the following:
(2,-7), (-10,8)
The formula used to find midpoint is: ![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%20%29)
We have ![x_1=2, y_1=-7, x_2=-10,y_2=8](https://tex.z-dn.net/?f=x_1%3D2%2C%20y_1%3D-7%2C%20x_2%3D-10%2Cy_2%3D8)
Putting values and finding midpoint
![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%20%29%5C%5CMidpoint%3D%28%5Cfrac%7B2-10%7D%7B2%7D%2C%5Cfrac%7B-7%2B8%7D%7B2%7D%20%29%5C%5CMidpoint%3D%28%5Cfrac%7B-8%7D%7B2%7D%2C%5Cfrac%7B1%7D%7B2%7D%20%29%5C%5CMidpoint%3D%28-4%2C0.5%20%29)
So, Midpoint is (-4,0.5)
Option A is correct.
Question 4
Find midpoint of the following:
(2,-10), (3,10)
The formula used to find midpoint is: ![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%20%29)
We have ![x_1=2, y_1=-10, x_2=3,y_2=10](https://tex.z-dn.net/?f=x_1%3D2%2C%20y_1%3D-10%2C%20x_2%3D3%2Cy_2%3D10)
Putting values and finding midpoint
![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%20%29%5C%5CMidpoint%3D%28%5Cfrac%7B2%2B3%7D%7B2%7D%2C%5Cfrac%7B-10%2B10%7D%7B2%7D%20%29%5C%5CMidpoint%3D%28%5Cfrac%7B5%7D%7B2%7D%2C%5Cfrac%7B0%7D%7B2%7D%20%29%5C%5CMidpoint%3D%282.5%2C0%20%29)
So, Midpoint is (2.5,0)
Option B is correct.
Question 5
Factor each completely
![x^2-3x-28](https://tex.z-dn.net/?f=x%5E2-3x-28)
We will break the middle term and find factors
![x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)](https://tex.z-dn.net/?f=x%5E2-3x-28%5C%5C%3Dx%5E2-7x%2B4x-28%5C%5CTaking%5C%3Acommon%5C%5C%3Dx%28x-7%29%2B4%28x-7%29%5C%5C%3D%28x%2B4%29%28x-7%29)
So, the factors are (x+4)(x-7)
Option C is correct.
Question 6
Factor each completely
![x^2+6x+8](https://tex.z-dn.net/?f=x%5E2%2B6x%2B8)
We will break the middle term and find factors
![x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)](https://tex.z-dn.net/?f=x%5E2%2B6x%2B8%5C%5C%3Dx%5E2%2B4x%2B2x%2B8%5C%5C%3Dx%28x%2B4%29%2B2%28x%2B4%29%5C%5C%3D%28x%2B4%29%28x%2B2%29)
So, the factors are (x+4)(x+2)
Option A is correct.
Answer:
2/6 which when simplified, is equal to 1/3