{letter in the word LOVE } {letter in the words MOVE}

Line segment AB has endpoints A(1, 2) and B(5, 3). Find the coordinates of the point that divides the line segment directed from

ikadub [295]

Now despite what you may think, 1:3 is not 1/3 in this situation, but rather it's "1 equal part to 3 equal parts", which is a total of 4 equal parts. In short, they want the point that is at the 1/4 mark from A to B.

Firstly, how many units apart is 1 to 5 (the x-coordinates)? That would be 4 units apart. Multiply 1/4 by 4:

$\frac{1}{4}\times \frac{4}{1}=\frac{4}{4}=1$

Next, how many units apart is 2 to 3 (the y-coordinates)? That would be 1 unit apart. Multiply 1/4 by 1:

$\frac{1}{4}\times \frac{1}{1}=\frac{1}{4}$

Next, since from 1 to 5 you are increasing, add 1 to 1.

$1+1=2$

2 is the x-coordinate of the new point.

Next, since from 2 to 3 you are increasing, add 1/4 to 2.

$2+\frac{1}{4}=2\frac{1}{4}=\frac{9}{4}$

9/4 is the y-coordinate of the new point.

Putting it together, the point which divides AB into a 1:3 ratio is (2, 9/4), or D.

4 0

3 years ago

An angle that is one half its arc is a/n ____________ angle.

Greeley [361]

Answer:

it's an inscribed angle

Step-by-step explanation:

4 0

3 years ago

Which function is linear?

natita [175]

Answer:

answer is b bro :)))))))))))))))

3 0

2 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago

Suppose a solid is formed by revolving the function f(x)=2+mx around the x-axis where 0≤m<1 and 0≤x≤1, and a washer is create

BabaBlast [244]

Answer:

(m³/3 + 5m/2 + 3)pi

Step-by-step explanation:

pi integral [(f(x))² - (g(x))²]

Limits 0 to 1

pi × integral [(2+mx)² - (1-mx)²]

pi × integral[4 + 4mx + m²x² - 1 + 2mx - m²x²]

pi × integral [m²x² + 5mx + 3]

pi × [m²x³/3 + 5mx²/2 + 3x]

Upper limit - lower limit

pi × [m²/3 + 5m/2 + 3]

Verification:

m = 0

[pi × 2² × 1] - [pi × 1² × 1] = 3pi

[m³/3 + 5m/2 + 3]pi

m = 0

3pi

3 0

3 years ago

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{letter in the word LOVE } {letter in the words MOVE}​

{letter in the word LOVE } {letter in the words MOVE}