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jonny [76]
4 years ago
10

What's the square root of 119?

Mathematics
1 answer:
dsp734 years ago
7 0
10.90871211463571 is the square root of 119
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Find the GCF OF 21 and 40
aniked [119]
The Greates Common Factor (GCF) is: 1
7 0
3 years ago
Nate rented a power washer and a generator. On his first job, he used each piece of equipment for 6 hours which cost $90. On his
sp2606 [1]

Answer:

Step-by-step explanation:

p = power washer and g = generator

6p + 6g = 90 .....multiply by 4

4p + 8g = 100 ....multiply by -6

---------------------

24p + 24g = 360 (result of multiplying by 4)

-24p - 48g = -600 (result of multiplying by -6)

---------------------add

-24g = - 240

g = -240 / -24

g = 10 <=== the generator cost $ 10 per hr

6p + 6g = 90

6p + 6(10) = 90

6p + 60 = 90

6p = 90 - 60

6p = 30

p = 30/6

p = 5 <==== the power washer costs $ 5 per hr

check...

4p + 8g = 100

4(5) + 8(10) = 100

20 + 80 = 100

100 = 100 (correct)

3 0
3 years ago
It shows the equations but it is a little confusing I don't want to get the problem wrong please help me out. Ill give you brain
Viktor [21]

Answer:εδΑΒΓΒΕ

U4\leq \sqrt{x} \sqrt[n]{x} 64

Step-by-step explanation:

73hsay  is a little bit too long and ∩679∨78ω8㏒∴≠÷±

6 0
2 years ago
Solving inequalities, what is x/18&gt;27
Lunna [17]

Answer:   x > 486

Explanation:

We have some number x and we divide that by 18. The result is larger than 27. To find possible values for x, we need to undo what is happening to x. The opposite of division is multiplication. We multiply both sides by 18 to cancel out the "18" on the left side, which will isolate x to get it to its own side.

This is what the steps look like

x/18 > 27

18*( x/18 ) > 18*27 .... multiplying both sides by 18

x > 486 ... note the 18's cancel on the left side

So this means x is some number greater than 486.

7 0
3 years ago
By Faraday's Law, if a conducting wire of length ℓ meters moves at velocity v m/s perpendicular to a magnetic field of strength
andrew11 [14]
V = -Bρv
dV/dv = -Bρ = -8 x 0.7 = -5.6
4 0
3 years ago
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