Riley makes a mistake in step 2 while doing her homework. What is the mistake?
2 answers:
We have been given work of Riley. By looking at his work carefully, we have to identify the error. So let's start from beginning.
First line is just the question so there will be no error.
After that we try to factor denominators
STEP1:
Factors are correct so no error in step1.
In step2, we have to find the common denominator which will be (x-2)(x-3)(x+3)
so that means she needs to multiply and divide 2nd term by (x-2)(x-3) while she multiplied by only (x-2). Which means she used wrong common denominator.
<u>Hence final answer will be "B. She used the wrong common denominator."</u>
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Answer:
156°
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
Here n = 15 , then
sum = 180° × 13 = 2340°
interior angle = =
= 156°
Answer:
Maximum profit at (3,0) is $27.
Step-by-step explanation:
Let quantity of products A=x
Quantity of products B=y
Product A takes time on machine L=2 hours
Product A takes time on machine M=2 hours
Product B takes time on machineL= 4 hours
Product B takes time on machine M=3 hours
Machine L can used total time= 8hours
Machine M can used total time= 6hours
Profit on product A= $9
Profit on product B=$7
According to question
Objective function Z=
Constraints:
Where
I equation
I equation in inequality change into equality we get
Put x=0 then we get
y=2
If we put y=0 then we get
x= 3
Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I
Now put x=0 and y=0 in I equation in inequality
Then we get
Hence, this equation is true then shaded regoin is below the line .
Similarly , for II equation
First change inequality equation into equality equation
we get
Put x= 0 then we get
y=2
Put y=0 Then we get
x=4
Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II
Point A and C are same
Put x=0 and y=0 in the in inequality equation II then we get
Hence, this equation is true .Therefore, the shaded region is below the line.
By graph we can see both line intersect at the points A(0,2)
The feasible region is AOBA and bounded.
To find the value of objective function on points
A (0,2), O(0,0) and B(3,0)
Put A(0,2)
Z=
At point O(0,0)
Z=0
At point B(3,0)
Z=
Hence maximum value of z= 27 at point B(3,0)
Therefore, the maximum profit is $27.
