The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
Answer:
x = 13
Step-by-step explanation:
x = 
12^2 + 5^2 = 13
Answer:
The slope is easy to find, just take 4 numbers. 10-2/-12-5 = 5.16666667 rounded to the nearest whole number is 6. So, your slope is 6.
Step-by-step explanation:
Answer:
She worked a total of 9 1/4 hours
She still owes her uncle $5.90
Step-by-step explanation:
29.95/2.60
6+1 3/4+1 1/2
9.25*2.60= 24.05
29.95-24.05= 5.90
