Answer:
As x → -∞, f(x) → 0.5; as x → ∞, f(x) → 0.5
Step-by-step explanation:
Given function:
<u>Asymptote</u>: a line that the curve gets infinitely close to, but never touches.
As the degrees of the numerator and denominator of the given function are equal, there is a horizontal asymptote at 
(where a is the leading coefficient of the numerator, and b is the leading coefficient of the denominator). This is the end behavior.
This is because as 
the -7 of the numerator and the +8 of the denominator become negligible. Therefore, we are left with:
Therefore:
R =4/3 (p-q)
3 x r = 4 (p-q)
(3 x r)/4 = p - q
(3 x r)/4 - q = p
Answer:
We have 197 g of Co-60 after 18 months.
Step-by-step explanation:
We can use the decay equation.
Where:
- M(f) and M(i) are the final and initial mass respectively
- λ is the decay constant (ln(2)/t(1/2))
- t(1/2) is the half-life of Co
- t is the time at the final amount of m
<u>Therefore, we have 197 g of Co-60 after 18 months.</u>
I hope it helps you!
The answer is x = 6
hope this helps
Answer:
please give me a brainless 0
Inequality :
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
The following is as far as I get:
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1
n−1−(⌊n÷m⌋×(a−b))≥x−α1a
n−(⌊n÷m⌋×(a−b))≥x−α1a + 1
Step-by-step explanation:
