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3 years ago

Select the interval where h(x)>0 {where h of x is greater than 0}

Mathematics

2 answers:

vazorg [7]3 years ago

6 0

Answer:

The correct option is;

Option 3. 2.5

Step-by-step explanation:

From the graph of the function y = h(x), where h of x h(x) > 0 and x > 0 we have;

The first interval where y =h(x) > 0 occurs between x= 0 and x = 0.8

The second interval where y =h(x) > 0 occurs between 2.2 and 4 which is a range of 4 - 2.3 = 1.7

The total interval where y =h(x) > 0 occurs is therefore = 0.8 + 1.7 = 2.5

Thus the function y = h(x), is positive over an interval on the x-axis = 2.5.

ehidna [41]3 years ago

3 0

Answer:

<h2>Option 3. 2.5</h2>

Step-by-step explanation:

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3 years ago

A coin collector has $45 in just dimes and quarters in a piggy bank he counted all the coins and there are 240 total how many ea

Whitepunk [10]

Answer:

The number of <u>dimes are 100</u> and number of <u>quarters are 140.</u>

Step-by-step explanation:

Let the number of dimes be 'd' and quarters be 'q'.

Given:

The sum of amount is $45.

The total number of coins are 240.

1 dime = $0.10

∴ 'd' dimes = $\$0.10d$

1 quarter = $0.25

∴ 'q' quarters = $\$0.25q$

Now, as per question:

$d+m=240-----1\\0.1d+0.25q=45---2$

Multiplying equation (1) by -0.1 and adding the result to equation (2), we get:

$-0.1d-0.1q=240\times -0.1\\-0.1d-0.1q=-24\\0.1d+0.25q=45\\-----------\\0.15q=21\\q=\frac{21}{0.15}=140\\\\d=240-q=240-140=100$

Therefore, the number of dimes are 100 and number of quarters are 140.

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3 years ago

Find the vertex of y=-x^2+6x-12

Debora [2.8K]

You find the x coordinates using x = -b/2a = -6/2(-1) = 3

Substitute 3 in the equation and find y

y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3

Vertex (3,-3)

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3 years ago