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alexdok [17]
3 years ago
15

Which two ratios form a proportion? A 1/ 2 and 4/2 B.2/1 and 4/8 C.1/2 and 8/4 D.2/1 and 16/8

Mathematics
2 answers:
N76 [4]3 years ago
6 0

Answer:

Option D

Step-by-step explanation:

LEts check each option

Simplify the fraction and check whether they are equal

Option A: \frac{1}{2} =\frac{4}{2}

\frac{1}{2} =2. they are not equal

Option B: \frac{2}{1} =\frac{4}{8}

\frac{2}{1} =\frac{1}{2}. they are not equal

Option C: \frac{1}{2} =\frac{8}{4}

\frac{1}{2} =\frac{2}{1}. they are not equal

Option D: \frac{2}{1} =\frac{16}{8}

\frac{2}{1} =\frac{2}{1}. they are equal

wel3 years ago
4 0

Two ratios form a proportion if they are equal. If one fraction is equivalent to the other fraction, they form a proportion. To find out, reduce both fractions and see if they are equal.

A

1/2 and 4/2

Reduce 4/2 to 2/1.

1/2 and 2/1 are not equal.

1/2 and 4/2 do not form a proportion.

B

2/1 and 4/8

Reduce 4/8 to 1/2.

2/1 and 1/2 are not equal.

2/1 and 4/8 do not form a proportion

C

1/2 and 8/4

Reduce 8/4 to 2/1.

1/2 and 2/1 are not equal.

1/2 and 8/4 do not form a proportion

D

2/1 and 16/8

Reduce 16/8 to 2/1

2/1 and 2/1 are equal.

2/1 and 16/8 form a proportion.

Answer: D. 2/1 and 16/8

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taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

 magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

OR

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

OR

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

OR

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I  I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

OR

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I  I never give negative answer

* The solution of Ix - 3I = -12 is ∅

4 0
3 years ago
The equation cos−1 = x can be used to determine the measure of angle BAC.
Sergio [31]

we know that

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the value of cosine of angle x is equal to

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we have

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Round to the nearest whole degree

x=70\°

therefore

<u>the answer is</u>

70\°


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