The number in the middle of a data set best describes

Because of high production-changeover time and costs, a director of manufacturing must convince management that a proposed manuf

7nadin3 [17]

Answer:

See explanation below

Step-by-step explanation:

Here, a director of manufacturing must convince management that a proposed manufacturing method reduces costs before the new method can be implemented. The current production method operates with a mean cost of $220 per hour.

a) The alternative and null hypotheses would be:

H0: μ ≥ 220

Ha: μ < 220

b) Comment on the conclusion when H0 cannot be rejected:

When we fail to reject the null hypothesis H0, there is not enough evidence to conclude that the mean cost can be reduced from $220. Therefore the manager's proposed method cannot be implemented.

c) Comment on the conclusion when H0 can be rejected:

When the null hypothesis, H0 is rejected, there is enough evidence to conclude that the mean cost can be reduced from from $220. Therefore the manager's proposed method can be implemented.

3 0

3 years ago

Jasmine took a cab Home form her office the cab charged a flat free of 4$ plus $2 per mile jasmine paid $33 for the trip how man

Lostsunrise [7]

33 - 4 = 29.

29 / 2 = 14.5

She traveled 14.5 miles in the cab.

Please mark Brainliest if it helped!

3 0

3 years ago

Read 2 more answers

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$