Answer:
Part A) The scale factor is ![2](https://tex.z-dn.net/?f=2)
The dimensions of the larger rectangular prism are
![Length=16\ ft](https://tex.z-dn.net/?f=Length%3D16%5C%20ft)
![Width=4\ ft](https://tex.z-dn.net/?f=Width%3D4%5C%20ft)
![Heigth=12\ ft](https://tex.z-dn.net/?f=Heigth%3D12%5C%20ft)
Part B) The volume of the smaller rectangular prism is ![96\ ft^{3}](https://tex.z-dn.net/?f=96%5C%20ft%5E%7B3%7D)
Part C) The volume of the enlarged rectangular prism is ![768\ ft^{3}](https://tex.z-dn.net/?f=768%5C%20ft%5E%7B3%7D)
Step-by-step explanation:
Part A)
we know that
If the dimensions of the prism are doubled, then the scale factor is equal to ![2](https://tex.z-dn.net/?f=2)
so
To find the dimensions of the larger rectangular prism, multiply the scale factor by the dimensions of the smaller rectangular prism
![Length=2*8=16\ ft](https://tex.z-dn.net/?f=Length%3D2%2A8%3D16%5C%20ft)
![Width=2*2=4\ ft](https://tex.z-dn.net/?f=Width%3D2%2A2%3D4%5C%20ft)
![Heigth=2*6=12\ ft](https://tex.z-dn.net/?f=Heigth%3D2%2A6%3D12%5C%20ft)
Part B) What is the volume of the smaller rectangular prism?
we know that
The volume of a rectangular prism is equal to
![V=LWH](https://tex.z-dn.net/?f=V%3DLWH)
we have
![L=8\ ft](https://tex.z-dn.net/?f=L%3D8%5C%20ft)
![W=2\ ft](https://tex.z-dn.net/?f=W%3D2%5C%20ft)
![H=6\ ft](https://tex.z-dn.net/?f=H%3D6%5C%20ft)
substitute the values
![V=8*2*6=96\ ft^{3}](https://tex.z-dn.net/?f=V%3D8%2A2%2A6%3D96%5C%20ft%5E%7B3%7D)
Part C) What is the volume of the enlarged rectangular prism?
we know that
The volume of a rectangular prism is equal to
![V=LWH](https://tex.z-dn.net/?f=V%3DLWH)
we have
![L=16\ ft](https://tex.z-dn.net/?f=L%3D16%5C%20ft)
![W=4\ ft](https://tex.z-dn.net/?f=W%3D4%5C%20ft)
![H=12\ ft](https://tex.z-dn.net/?f=H%3D12%5C%20ft)
substitute the values
![V=16*4*12=768\ ft^{3}](https://tex.z-dn.net/?f=V%3D16%2A4%2A12%3D768%5C%20ft%5E%7B3%7D)
Remember that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z------> scale factor
x-----> volume of the enlarged prism
y-----> volume of the smaller prism
so
![z^{3}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B3%7D%3D%5Cfrac%7Bx%7D%7By%7D)
![x=y*z^{3}](https://tex.z-dn.net/?f=x%3Dy%2Az%5E%7B3%7D)
we have
![z=2](https://tex.z-dn.net/?f=z%3D2)
![y=96\ ft^{3}](https://tex.z-dn.net/?f=y%3D96%5C%20ft%5E%7B3%7D)
substitute
---> is ok
First, change the mixed fraction into improper fraction
1 1/7 = 7/7 + 1/7 = 8/7
(4/7)/(8/7)
To solve, flip the second fraction, and change the division into multiplication
(4/7)/(8/7) = (4/7) x (7/8)
Multiply, and simplify
(4/7) x (7/8) = 28/56, or 1/2
1/2 is your answer
hope this helps
Answer:
i have this question too. im not sure but i think its maximum
Step-by-step explanation:
Supplementary angle = Angels which add up to 180 degrees
Angle CED
Answer:
-4.
Step-by-step explanation:
5(m - 1) = -25
m - 1 = -5
m = -4.