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3 years ago

Jason earned $54 at his job when he worked for 4 hours. What was his hourly pay rate in hours per dollar?

Mathematics

1 answer:

leva [86]3 years ago

6 0

Answer:

$13.50

Step-by-step explanation:

$54 divided by 4 is $13.50.

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Claudia spends $2.15 a day for lunch. Her cafeteria lunch account has a balance of $48.00. Which equation can be used to determi

andreev551 [17]

Answer:

d≤48/2.15

Step-by-step explanation:

Step one:

Given data

Claudia spends $2.15 a day for lunch.

We are told that her balance is $48.00

let the number of days be d

Step two:

The maximum number of days she can eat is given as

d≤48/2.15

d≤22.33 days

7 0

2 years ago

The first T-shirt you buy costs $7, and every additional shirt costs only $5. Let f(n) be the total cost of n shirts. F is a seq

Zina [86]

Answer:

f(n) = 2 + 5n. This is an arithmetic sequence.

Step-by-step explanation:

f(1) = 7

f(2) = 7 + 5

f(3) = 7 + 5 + 5 = 7 +10

f(4) = 7 + 5 + 5 + 5 = 7 + 15

In general,

f(n) = 7 + 5(n -1 )

= 7 + 5n - 5

= 2 + 5n

We have the sequence 7, 12, 17, 22, 27 …

This is an arithmetic sequence, because it is a sequence of numbers in which the <em>common difference</em> between consecutive terms is 5.

6 0

3 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$