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yaroslaw [1]
3 years ago
7

Which equation represents a line that passes through (-2, 4) and has a slope of 1/2?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

\large\boxed{y-4=\dfrac{1}{2}(x+2)\text{- point-slope form}}\\\boxed{y=\dfrac{1}{2}x+5\text{- slope-intercept form}}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

We have the slope m=\dfrac{1}{2} and the point (-2, 4).

Substitute:

y-4=\dfrac{1}{2}(x-(-2))

y-4=\dfrac{1}{2}(x+2) - point-slope form

Convert to the slope-intercept form (y = mx + b):

y-4=\dfrac{1}{2}(x+2)      <em>   use the distributive property</em>

y-4=\dfrac{1}{2}x+1         <em>add 4 to both sides</em>

y=\dfrac{1}{2}x+5 - slope-intercept form

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m =(-2 + 3 )/(-3 -2)

m = 1/-5

m = -1/5

slope of the line that is perpendicular  = 5


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Answer:

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Step-by-step explanation:

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, then m=m equals negative StartFraction 1 Over 6 EndFraction.. What is the value of b?

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