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yaroslaw [1]
3 years ago
7

Which equation represents a line that passes through (-2, 4) and has a slope of 1/2?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

\large\boxed{y-4=\dfrac{1}{2}(x+2)\text{- point-slope form}}\\\boxed{y=\dfrac{1}{2}x+5\text{- slope-intercept form}}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

We have the slope m=\dfrac{1}{2} and the point (-2, 4).

Substitute:

y-4=\dfrac{1}{2}(x-(-2))

y-4=\dfrac{1}{2}(x+2) - point-slope form

Convert to the slope-intercept form (y = mx + b):

y-4=\dfrac{1}{2}(x+2)      <em>   use the distributive property</em>

y-4=\dfrac{1}{2}x+1         <em>add 4 to both sides</em>

y=\dfrac{1}{2}x+5 - slope-intercept form

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Answer:

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y = -4x + 7        (II)

One way is to rewrite the second as

4x + y = 7

Now multiply this equation by 8

32 x + 8 y = 56

9 x + 8 y = 10        and now subtract the equations

23 x = 46     this gives x as 2

From equation (II)  y = -4 (2) + 7  = -1

So our values are (2, -1)

Check:

(I) 9 x + 8 y = 10         9 * 2 - 8 = 10

(II)  4 x + y = 7       or 4 * 2 - 1 = 7

Or you can substitute equation (II) directly into equation (I)

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Answer:

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Step-by-step explanation:

6(x-8)= x- (8)

6x - 48=x - 8

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2 years ago
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Answer:

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Answer:

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